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Filtering out duplicates with the highest version number

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# 1  
Old 10-29-2012
Filtering out duplicates with the highest version number


I have a huge text file with filenames which which looks like the following ie uniquenumber_version_filename:


What I need to do is examine the file, look for duplicate uniquenumbers and then filter out the uniquenumber with the highest version, so for example in the above it would be the following:

Is there a scripted method by which I can do this?

Thanks in advance

Last edited by Franklin52; 10-30-2012 at 08:12 AM.. Reason: Please use code tags for data and code samples
# 2  
Old 10-29-2012
awk -F_ ' { a=$1; b=$2; getline; c=$1; d=$2; if(a==c) { if(b<d) $0=$0; } else { getline; $0=""; e=$1; f=$2; if(d<f) $0=""; } }  { print; } '  infile

# 3  
Old 10-29-2012
That's an amazing solution sir, but it looks abit complicated.

Also will I will be able to apply it to a huge file full of uniquenumber_version_filename with thousands of rows?

# 4  
Old 10-29-2012
Another awk solution:

awk -F_ '$2>0+V[$1]{V[$1]=$2;F[$1]=$0} END{for(k in V) print F[k]}' OFS=_ infile

This should work for quite large files, however the output will be unsorted, you didn't specify if the file order was important.
# 5  
Old 10-29-2012
If the field "uniquenumber" is clustered together along with the "version" in order (as shown in your example), you can use:

awk -F_ '{ if ( ($1 != u) && (v > 1) ) { print l } u=$1; v=$2; l=$0 }' yourfile

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