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Date conversion help from dd/mm/yyyy to dd/Mon/yyyy i.e. 28/10/2012 to 28/Oct/2012

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# 1  
Old 10-29-2012
Date conversion help from dd/mm/yyyy to dd/Mon/yyyy i.e. 28/10/2012 to 28/Oct/2012
Hi I have a problem with Date format in my code.

1st I am trying to convert today's date to yesterday's using
Code:
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y[5]+1900,$y[4]+1,$y[3];$y[3];'`

And once it is done I am trying to using the yesterday date in a grep command to compare a logfile. But, the date format in logfile is 28/Oct/2012.

Could you please help me convert 28/10/2012 to 28/Oct/2012.

Thank You!
Last edited by Franklin52; 10-30-2012 at 07:13 AM.. Reason: Please use code tags for data and code samples
# 2  
Old 10-29-2012
https://www.unix.com/shell-programmin...-jan-12-a.html

---------- Post updated at 09:01 PM ---------- Previous update was at 09:00 PM ----------

https://www.unix.com/shell-programmin...rmat-perl.html
# 3  
Old 10-29-2012
It worksSmilie...Thank you!Smilie
# 4  
Old 10-31-2012
Or use dateutils, e.g.

Code:
dconv yesterday -f '%Y/%b/%d'

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