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awk pattern matching on ssh

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# 1  
Old 10-29-2012
awk pattern matching on ssh
Hi folks,

i am trying to filer some log file using awk command. When i try it on remote server, it can show the result.

Code:
awk '$1=="2012-10-29" && $4==17353' somelogfile

But when i try to execute it from ssh, it cannot show the same result.

Code:
ssh someserver "awk '\$1=="2012-10-28" && \$4==17353' somelogfile"

I suspect this must because of the date format (2012-10-29), because when i try to do one pattern matching only using awk script below, it can produce the result.

Code:
ssh someserver "awk '\$4==17353' somelogfile"

Please advise since i am still a newbie about all this scripting stuff


Thanks
# 2  
Old 10-29-2012
try

Code:
ssh someserver "awk '$1==\"2012-10-28\" && $4==17353' somelogfile"

# 3  
Old 10-29-2012
Code:
ssh someserver "awk '\$1==\"2012-10-28\" && \$4==17353' somelogfile"

@pamu, your solution will not work. You are allowing the shell to interpret $1 and $4 in that double-quoted string.
Last edited by elixir_sinari; 10-29-2012 at 02:39 PM..
# 4  
Old 10-29-2012
Quote:
Originally Posted by elixir_sinari
@pamu, that'll not work. You are allowing the shell to interpret $1 and $4 in that double-quoted string.
Sorry for this...

Not used ssh yet...Smilie

ThanksSmilie
This User Gave Thanks to pamu For This Post:
howielim
# 5  
Old 10-29-2012
There's nothing ssh specific there. It's how a command pipeline is interpreted by the shell.
# 6  
Old 10-29-2012
Quote:
Originally Posted by elixir_sinari
Code:
ssh someserver "awk '\$1==\"2012-10-28\" && \$4==17353' somelogfile"

@pamu, that'll not work. You are allowing the shell to interpret $1 and $4 in that double-quoted string.
Strangely, this scripts works. My complete awk commands is

Code:
ssh someserver "awk '\$1==\"2012-10-28\" && \$4==17353' somelogfile"

However i also found a way to use value on those date. Just sharing my alternative script

Code:
ssh someserver "awk -v date=2012-10-28 -v id=17353 '\$1 == date && \$4 == id' somelogfile"

Quote:
Originally Posted by elixir_sinari
There's nothing ssh specific there. It's how a command pipeline is interpreted by the shell.
nevermind it is solved now. Really appreciate your advice just now. Thanks to pamu and elixir_sinari
# 7  
Old 10-29-2012
If you need to know the exact command seen by ssh (which will be passed to your remote server), just add an echo before the ssh command line.
Code:
echo ssh someserver "awk -v date=2012-10-28 -v id=17353 '\$1 == date && \$4 == id' somelogfile"

ssh someserver awk -v date=2012-10-28 -v id=17353 '$1 == date && $4 == id' somelogfile

So, the last line shows the exact command seen by ssh after shell interpretation.

BTW, the working solution is the one suggested by me, isn't it?
Last edited by elixir_sinari; 10-29-2012 at 02:11 PM..
This User Gave Thanks to elixir_sinari For This Post:
howielim
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