Bash script with arguments


 
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# 1  
Old 10-24-2012
Bash script with arguments

Could someone help me with the script below?
I am trying to make a script having just one arguement as a command and then it executes the appropriate code
Code:
#!/bin/bash
if [ "$1" = "listCommands" ]
then
   echo "Available commands:"
   echo "./exec.sh cmd1"
   echo "./exec.sh cmd2"
elif [ "$1" = "cmd1" ]
then
   cmd1 = /mnt/share20/ikausr/utilities/test.sh
   log = /mnt/share20/ikausr/utilities/test.log
   sh $cmd1>>$log 2>&1
elif [ "$1" = "cmd2" ]
then
   echo "..........second command"
else
   echo "you haven't chosen any command"
fi

Error::
Code:
$ exec.sh cmd1
./exec.sh: line 9: cmd1: command not found
./exec.sh: line 10: log: command not found
./exec.sh: line 11: $log: ambiguous redirect

Any help?

Last edited by spiridakos; 10-24-2012 at 09:33 AM.. Reason: Please use code tags for data and code samples
# 2  
Old 10-24-2012
Remove all the spaces around the "=" sign.
Code:
cmd1=/mnt/share20/ikausr/utilities/test.sh

instead of:
Code:
cmd1 = /mnt/share20/ikausr/utilities/test.sh

etc....
This User Gave Thanks to Franklin52 For This Post:
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