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some months ego

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# 1  
Old 07-26-2005
some months ego
Hi,
how can I format date function to find n (n=1 to 11) months ego ?
For exemple now we are in july and I want to have a variable presenting april.
How should it be :
month=`date +%b`?????
Many thanks before.
# 2  
Old 07-26-2005
Look into this

Could be helpful.

Vino
# 3  
Old 07-26-2005
Thanks , but a problem :
/u04/>date -v -2m
date: illegal option -- v
date: illegal option -- 2
date: illegal option -- m
usage: date [-u] mmddHHMM[[cc]yy][.SS]
date [-u] [+format]
date -a [-]sss[.fff]
# 4  
Old 07-26-2005
Looks like you are running Solaris.

And you issuing a command which worked under FreeBSD.

vino
# 5  
Old 07-26-2005
Yes I'm under Solaris and this :
mois=`date +%b`; export mois
functions. i get mois=Jul. How can I get two or three month earlier ?
Many thanks.
# 6  
Old 07-26-2005
7 months ago:

ruby -e "t=Time.now.to_a;t[4]-=7;(t[4]+=12;t[5]-=1) if t[4]<1;puts Time.local(*t).strftime('%b')"
# 7  
Old 07-26-2005
Code:
#!/bin/ksh

thisMonth=$(date +%b)
monthsBack=2

echo "thisMonth->[${thisMonth}]"
echo "${monthsBack}-months back-> [$(nawk -v month="${thisMonth}" -v back="$monthsBack}" '\
  BEGIN{n=split("Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec", year);
        for(i=1; i <= n; i++)
           if ( month == year[i]) {
              print ( i > back) ? year[i-back] : year[n-(back-i)]
           }
  }
')]"

Last edited by vgersh99; 07-26-2005 at 03:38 PM..
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