Shell Programming and Scripting

Hi,

The record length may be differ in afile. I want to display the records if the record length is not equal to 50 using sed/awk command.

Thanks in Advance

I hope you mean a line by "record".

Code:

awk 'length!=50' file

or

Code:

sed -n '/^.\{50\}$/!p' file

I hope the file contains only ASCII characters.

the file contails wide characters and sed command failed "

Code:

Function ... cannot be parsed"

and

Code:

awk

command displays all the records

What's the encoding?

You should also state the operating system version you're using.

Is 50 the actual value that you're using or is it something larger?

And, please, don't edit error messages. Paste them verbatim whenever possible (I'm assuming that "..." in "Function ... cannot be parsed" is a placeholder).

Regards,
Alister

am using OS : AIX
exact length is 400

Code:

sed: 0602-404 Function /^.\{400\}$/!p cannot be parsed.

The record has pipe line characters "|"

If the length 20 or 50 is working file. I think length 400 is the problem

Thanks for providing the additional information.

While it may not be relevant to this problem, in the future please be specific when you state your OS. There is more than one version of AIX out there.

Pipe characters should not be a problem.

I believe your sed implementation only supports the closed interval 0 to 255.

Perhaps you can work around it thusly:

Code:

sed 'h; s/.\{200\}//; /^.\{200\}$/d; g'

Note that it is logically required for the first count to be less than or equal to the second. Otherwise, erroneous results will ensue.

I'm curious regarding why your awk attempt did not work.

Regards,
Alister