Replace date on a line with current date


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# 1  
Replace date on a line with current date

Hi Guys,
I have a file with following content

Code:
From 20121014 : To 20121014
Number of days : 1 
1234
1245
1246
1111

Everyday i run my script i want to modify "To" date on the first line with current date. I have set the current date in script as

Code:
RUN_DATE=`date -u +%Y%m%d`

So i want to replace "To" date with $RUN_DATE. The "From" date never changes.
Also, i want to replace on second line (toDate-fromDate)+1. Right now it is 1. So when it runs tomorrow it should be 2.
Thanks - jak
# 2  
Assuming, the line always be the first line..

Code:
awk 'NR==1 {$NF=date}1' date=$RUN_DATE file

# 3  
Thanks clx - yes it will always be on 1st line. Also, how would i modify the second line with the difference between two days(numbers) + 1

Thanks for your help! _ jak

---------- Post updated at 02:47 PM ---------- Previous update was at 11:53 AM ----------

Correction on previous post. I need difference of two dates and not numbers update on line 2.

Thanks - jak
# 4  
Do you have GNU date?
# 5  
Yes. I tried this on my shell

Code:
date +"%Y%m%d" -d sunday 
20121021

# 6  
Try...
Code:
awk ' NR == 1 {
              from = $2
              "date -u +%Y%m%d" | getline to
              $NF = to
      }
      NR == 2 {
              "expr $(date -d " to " +%s) - $(date -d " from " +%s)" | getline diff
              $NF = int(diff / 86400) + 1
      }
      {
              print $0
      }
      ' file1 > file2


Last edited by Ygor; 10-15-2012 at 12:54 PM..
# 7  
Hi Ygor,

I tried and am getting this error when i run

Code:
sh: -c: line 0: syntax error near unexpected token `)'
sh: -c: line 0: ` +%s)'

thanks - jak
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