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Shell Programming and Scripting

number of instance check

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# 1  
Old 10-14-2012
number of instance check
Hi,

We are getting a curios result in one of AIX script. Its executed using !/bin/ksh .

After following line we get result of 3 in in the variable instance_count.
Code:
instance_count=`ps -ef | grep "script_check_instances.sh" | grep -v "grep" | wc -l`

But once we do a "ps -aef | grep script_check_instances.sh" just after instance_count calculation this is what we get

Code:
2012-10-13 17:49:59 : the count of instances of the script script_check_instances.sh running in the system is :        3
2012-10-13 17:49:59 : Processes that are running currently using the script script_check_instances.sh are below - thus exiting:
2012-10-13 17:49:59 : xawm_unx  5374176 11337812   0 17:49:59      -  0:00 grep script_check_instances.sh
xawm_unx 11337812  7078552   1 17:49:59      -  0:00 /bin/ksh /x01bkatlmr198/applicat/app/scripts/script_check_instances.sh

This issue have repeate for many times. Have any one faced a simmilar issue.

Regards,
Abin Peter.
Last edited by Franklin52; 10-14-2012 at 07:18 AM.. Reason: Please use code tags
# 2  
Old 10-14-2012
Quote:
Originally Posted by niba
instance_count=`ps -ef | grep "script_check_instances.sh" | grep -v "grep" | wc -l`

But once we do a "ps -aef | grep script_check_instances.sh" just after instance_count .
Please use code tags for sample data and code.

What is the issue...?

if you are talking about 4 lines from second command then just check the difference.

Code:
ps -ef | grep "script_check_instances.sh" | grep -v "grep" | wc -l

Code:
ps -aef | grep script_check_instances.sh

# 3  
Old 10-19-2012
grep -v "grep" from 1st command should remove the grep line from out put and the instance_count should be 1. Whay am I getting 2 instead?
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