Shell Programming and Scripting

Hi,

I need to get specific parts in a large file.

I need to:
Get a line containing an IP address, and read from there to another line saying ***SNMP-END***

So, I have the start and the end well defined, but the problem is that apparently the awk command using the -F option doesn't work good with the IP address, let's say 1.1.1.1

Originally the text it will be like this:

Code:

***SNMP-ST***
IP = 1.1.1.1
some text here
***SNMP-END***

That's what I have been trying to do, btw .. the file contains thousands of IP addresses and some of these 1.1.1.1, which are the ones I need to capture.

Any help is greatly appreciated.

This seems to print all of the lines you have labeled above as "some text here":

Code:

awk '/^IP = 1\.1\.1\.1$/{copy=1;next} /SNMP-END/{copy=0;next} copy' in

Thanks for the reply.

For some reason I am getting the following error.

awk: syntax error near line 1
awk: bailing out near line 1
Exit 2

I am using solaris, not sure if changes something

---------- Post updated at 04:32 PM ---------- Previous update was at 04:27 PM ----------

Apparently it doesn't like the "copy", if I remove them it does something, obviously not what I am expecting, but it moves.

Can't you simply run below command and get rid of lines starting with IP and ending with *:-

Code:

cat input | egrep -v "^IP|\*$"

On Solaris systems use nawk or /usr/xpg4/bin/awk instead of awk.

---------- Post updated at 02:47 PM ---------- Previous update was at 02:45 PM ----------

He said he only wants lines from entries with IP address 1.1.1.1.

Code:

awk '/IP *= *1\.1\.1\.1/ {print;while($0!~ /SNMP-END/){getline;print;}}' input_file

or
as Don Cragun has pointed out use nawk

Code:

nawk '/IP *= *1\.1\.1\.1/ {print;while($0!~ /SNMP-END/){getline;print;}}'  input_file

Thanks guys, the last post from msabhi did the trick! but I was also able to get a lot of good things from the previous answers.

thanks,