Shell Programming and Scripting

It might be a bit easier to do it with "sed" - at least it is shorter to write:

Code:

sed -n '/^IP *= *1\.1\.1\.1/,/SNMP-END/p'

I hope this helps.

bakunin

What is the meaning of....
while($0!~ /SNMP-END/). ??

I know what it is doing, but I don't understand the $0!...

Thanks

! indicates not.
like !=--> Not equal to
like !~--> Not contains

And

$0!~ /SNMP-END/ means $0 not contains /SNMP-END/. It is true when line not containing search criteria..

Hope this helps you

Hi,

Now I need to add something else to the command, the current one works just great, but I need to ... get some number of lines before and read to the end.

awk '/IP *= *1\.1\.1\.1/ {print;while($0!~ /SNMP-END/){getline;print;}}' input_file
That will look for 1.1.1.1 and will read until SNMP-END, but I will need to get the whole block, adding also the SNMP-ST for the groups including 1.1.1.1

If someone can help, it will be great.

Thanks,

Code:

perl -lne '{if(/SNMP-ST/){$#A=-1;$f=1;}
if(/IP/){$f=(/1\.1\.1\.1/)?1:0;}if(/SNMP-END/ && ($f)){print join("\n",@A,$_);next}($f)?push(@A,$_):next;}' input_file

holy guacamole!!! .. that was great!

thanks

You can do it in sed (which is probably faster than PERL) with the following algorithm: collect all lines, starting from the beginning of a block to and ending with the end of a block, in a buffer. Then print only the blocks which contain the search string and clear the buffer then, regardless of it being printed or not:

Code:

sed -n '/\*\*\*SNMP-ST\*\*\*/,/\*\*\*SNMP-END\*\*\*/N
        /\*\*\*SNMP-END\*\*\*/ {
             /IP *= *1\.1\.1\.1\./p
             d
        }' /path/to/infile

I hope this helps.

bakunin