Shell Programming and Scripting

Even I make the values into variables, the data after @ is skipped. Please help.

Hello Friends,

The above PERL works only for Alphabets and not for Alphanumeric or with Special characters.

Since that will be a Password column, User can provide any Character sequence. Please suggest some other Solution.

Try this:

Code:

perl -e '$exists=shift @ARGV;$from=shift @ARGV;$to=shift @ARGV;
$fromlen=length($from);$tolen=length($to);
$^I=".bak";
while(<>) {
 if(index($_,$exists) != -1) {
  while(($s=index($_,$from,$nxt)) != -1) {
   substr($_,$s,$fromlen,$to);
   $nxt=$s+$tolen;
  }
 }
 print;
}' 'sathya' '123' 'S@THYA01' infile

The first argument (sathya in this case) is the "string" which should be present in the line to attempt substitution.
The second argument (123 here) is the "string" you want to search for.
The third argument (S@THYA01 here) is the replacement "string".
The fourth argument (infile here) is the file to be changed.
Backup of the original file will be taken with .bak extension.

Many thanks Knight. How can we include this in it

Code:

if /sathya/'

Code:

find . -type f -print | xargs perl -p -i -e "s/pattern search string/replace string /g"

I've edited my earlier post. Check it now.

Thanks Knight, I will check it.

@Saud Pasha: I should have to specify my file name in the find, isn't it ?

find . -name "filename" -type f | xargs perl -p -i -e "s/pattern search string
/replace string /g"

also not only that, I have to find out a pattern "sathya" and only after that I have to replace the value of its 3rd column.

---------- Post updated 10-16-12 at 02:00 AM ---------- Previous update was 10-15-12 at 03:41 AM ----------

Thanks Knight , it works

---------- Post updated at 02:42 AM ---------- Previous update was at 02:00 AM ----------

Why the below is not working ?

My file is

Code:

>> cat test.txt
sathya yuiop New
ramesh sdgh 456
santhosh sdghsdf 789

I just want to try how this works with the awk as said by itkamaraj.

Code:

#!/bin/sh

var1=sathya
pwd=New
npwd=S@thya01


echo $pwd $npwd | awk -v var=$var1 '/var.*$1/{gsub("$1","$2")}1' test.txt > temp.txt
cat temp.txt > test.txt
rm temp.txt

After executing the above, my file contents remains the same.

But if I execute the awk statement without variables, it works as expected.
Please advise me on what am i missing.