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capture all the today files

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# 1  
Old 07-22-2005
capture all the today files
My folder (e.g. /opt/successlog/) creates many files thru cron jobs everyday. I would like to retreive all the today files in this folder into a log file. How to do this for KSH? Thanks!
# 2  
Old 07-22-2005
Check out Perderabo's solution in https://www.unix.com/shell-programming-and-scripting/13858-find-command.html

Vino
# 3  
Old 07-25-2005
Thanks Vino! It works great.
# 4  
Old 07-28-2005
You can also check a different option for find command -

Quote:
-daystart
Measure times (for -amin, -atime, -cmin, -ctime, -mmin, and
-mtime) from the beginning of today rather than from 24 hours
ago.
For example -
Code:
EDIDIR=${LMS_EDI_IN}/${COMP}/${DIR}
FTPDIR=${LMS_VAR}/ftp/${COMP}/${DIR}
EDIINLIST=/app/lms/common/logs/admin/systemhealth/checkdailyinbounce_{$COMP}_${DIR}.log

find ${EDIDIR} -name "*.${EXT}" -daystart -mtime 0 -type f -exec ll {} \; > $EDIINLIST
find ${FTPDIR} -name "*.${EXT}" -daystart -mtime 0 -type f -exec ll {} \; >> $EDIINLIST

if [ ! -s $EDIINLIST ]
then
        echo "No ${REPNAME} file(s) received by LMS" | mailx -s "No inbound ${REPNAME} files for ${COMPNAME} received by LMS today " $MAILDL
else
        echo File Found
        cat $EDIINLIST
fi

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