Shell Programming and Scripting

Hi,
Can some tell me how can i read a file sequentially i.e one line after other , which contains list of commands.

For ex :
My src_file looks like

awk -F:"-" '/abc/ {print $1}
awk -F:"-" '/zzz/ {print $1}
awk -F:"-" '/ppp/ {print $1}

I tried with for loop like this,

for i in `cat src_file`
do
echo $i
done

Since for loop take evry space as an entry, my output breaksup at every space & shows like
awk
-F:"-"
'/abc/
{print $1}
...
..
however my required output is awk -F:"-" '/abc/ {print $1}

Can someone throw some light ??

Thanks
Brian

Code:

#!/bin/ksh

while read line
do
  echo $line
done < src_file

yes that would surely work... put it in while loop... to be presice.. if the file name is abc.txt.. it will look like..
cat abd.txt | while read line
do
echo $line
done

and in the loop you can do what ever you want with the line.... like cut etc !!....

that was typo !!... :-o) typed abd.txt instead of abc.txt.....

cat abc.txt | while read line
do
echo $line
done

this is a UUOC - don't 'cat' through the pipe - use 'file redirection'.

Hi,
Thanks a lot for your inputs,It worked,but i just got into another problem
now my script looks like

Code:

     1 #!/bin/ksh
      2 #set -x
      3 cd $PM_HOME/Scripts
      4
      5 while read ln
      6 do
      7 echo "VALUE IS : $ln"
      8 v1=`cut -f3 -d";"`
      9 echo $v1
     10 v2="$v1"
     11 echo $v2
     12 done < test.in
~

and my input file test.in looks like

As mentioned before, my objective is read every line of the file contains commands, then execute it & then store it a variable.

However, I'm unable to execute the command, it's just stores it as string, inspite I've included backquotes in the sourcefile. Any reasons why ?

don't need the back-quotes in the file, but just in case you do have them - I remove them
not tested........

Code:

#!/bin/ksh

while IFS=';' read foo foo cmd
do
  cmd=$(echo ${cmd} | sed 's/`//g')
  echo "cmd->[${cmd}]"
  var=eval ${cmd}
  echo "var->[${var}]"
done < test.in