script to tell whether there exists directory or not

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10-10-2012

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The value of ? ($?) which you are testing is for the echo $ver statement (which will almost always be true (0)) and subsequently, only 12.5.txt will be appended to.

You don't seem to be needing the awk command.

Try:

Code:

#!/bin/sh
set -x
for i in `cat serverlist`; do
sleep 2
vtask $i ". /etc/profile.CA all; dsmver" > version.txt
#ver=`awk '{while(match($0,/12\.5\.0\.2307/)) {  print substr($0,RSTART,RLENGTH) sub(/12\.5\.0\.2307/,"")}}' version.txt | sort -u`
#echo $ver
#if [ $? -eq 0 ];
if fgrep -q "10.12.2.2307" version.txt 2>/dev/null
then
print $i >> 12.5.txt
else
print $i >> 12.0.txt
fi
done

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