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if characters from positions 7-15 are matching 219 then replace al

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Top Forums Shell Programming and Scripting if characters from positions 7-15 are matching 219 then replace al
# 1  
Old 10-02-2012
if characters from positions 7-15 are matching 211-219 then replace
Script for if characters from positions 7-15 are matching with characters from position 211-219 then replace all char from 211-219 with 9 space.
Total length of record is 420. Here is the specification of the data in file.
Code:
Position    Field Data Type
-----------------------------------------------------
1          Capital Letter total length = 1
2-6          Blanks
7-15         Numeric Data total length 9
16-19       Numeric Data total length 4
20-25       Year and Month.
26-31        Blanks
32           Character Data total length 1
33           Character Data total length 1
34-41        Blanks
42-43        Character Data total length 2
44-48        Blanks
49          Capital Letter total length = 1
50-89          Character total 39 length
90-129        Character total 39 length 
130          Capital Letter total length = 1
131-170          Character Data total length 39
171-199         Alphabetic Data total length 29
200-201         Character Data total length 2
202-210         Numeric Data total length 5
211-219         Numeric Data total length 9
220-290         Character Data total length 60
291-330          Character Data total length 39
331-359       Alphabetic total length 29 character 
360-361       Character Data total length 2
362-370       Numeric Data total length 5
371           Capital Letter total length = 1
372-420         Blanks

Any help on this will be appreciated. Thanks in advance.
Last edited by lancesunny; 10-03-2012 at 11:23 AM..
# 2  
Old 10-02-2012
Code:
awk -f a.awk infile > newfile

where a.awk:
Code:
{
  str1=substr($0,1,6);
  str2=substr($0,7,9);
  str3=substr($0,16,211-16);
  str4=substr($0,211,9);
  str5=substr($0,220);
  if (str2 == str4) gsub(".", " ", str4);
  print str1 str2 str3 str4 str5;
}

This User Gave Thanks to rdrtx1 For This Post:
lancesunny
# 3  
Old 10-03-2012
Thanks rdrtx1.
I will test your solution tomorrow and let you know.
Thanks for your time and help regarding this.

---------- Post updated 10-03-12 at 10:21 AM ---------- Previous update was 10-02-12 at 10:32 PM ----------

Thanks for you help rdrtx1.
I am getting following error when i run it
$ awk -f { str1=substr($0,1,6); str2=substr($0,7,9); str3=substr($0,16,211-16); str4=substr($0,211,9); str5=substr($0,220); if (str2 == str4) gsub(".", " ", str4); print str1 str2 str3 str4 str5; } input.dat > output.dat
-bash: syntax error near unexpected token `('

---------- Post updated at 10:53 AM ---------- Previous update was at 10:21 AM ----------

Thanks you all for you help & time on this one.
Here is the code which worked fine.
Code:
awk 'substr($0,7,9)==substr($0,211,9){
$0=substr($0,1,210) sprintf("%9s",x) substr($0,220)
}1' file

ThanksSmilie
-LanceSunny
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