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Script using Wait

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# 1  
Old 10-02-2012
Script using Wait
Hi,


written a script which uses wait as follows

Code:
Main.sh

#!/usr/bin/ksh

nohup scrpit1 1 &
pid_1=$!
nohup scrpit1 2 &
pid_2=$!
wait $pid_1
wait $pid_2

nohup scrpit1 3 &
pid_1=$!
nohup scrpit1 4 &
pid_2=$!
wait $pid_1
wait $pid_2

So like that i have more 30 nohups with wait and running 2 inputs simultaneously.


But i want to run the nohup based on number of wait's in the loop

Example

in the above main.sh, when i execute the script

I see two script will run simultaneously. But both should complete to run next set of Nohups. Instead of that...i want a script which will invokes 2 nohup with different inputs first. If one completes than it should kick of the other nohup with different input simultaneous.

Current Situation

Code:
ps -eaf | grep Main.sh

root   17026 32470  0 00:31 ?        00:00:00 /usr/bin/ksh ./Main.sh 1
root   17027 32470  0 00:31 ?        00:00:00 /usr/bin/ksh ./Main.sh 2

After Some time

ps -eaf | grep Main.sh

root   17027 32470  0 00:31 ?        00:00:00 /usr/bin/ksh ./Main.sh 2


Requirement


ps -eaf | grep Main.sh

root   17026 32470  0 00:31 ?        00:00:00 /usr/bin/ksh ./Main.sh 1
root   17027 32470  0 00:31 ?        00:00:00 /usr/bin/ksh ./Main.sh 2


after some time

ps -eaf | grep Main.sh

root   17027 32470  0 00:31 ?        00:00:00 /usr/bin/ksh ./Main.sh 2
root   17028 32470  0 01:31 ?        00:00:00 /usr/bin/ksh ./Main.sh 3

Please help guys...
# 2  
Old 10-02-2012
What about this different approach?
The example below is for 4 total instances, 2 of them run simultaneously.
Code:
i=0; while((i<=4)); do while (( $(pgrep -c myscript) < 2 )); do let i++ ; nohup ./myscript $i >/dev/null 2>&1 & done; done &

If your parameters are not really numbers, you can put them in an indexed array:

Code:
arr=( par1 par2 par3 par4 )
i=0; while((i<=${#arr[@]})); do while (( $(pgrep -c myscript) < 2 )); do  nohup ./myscript ${arr[$i]} >/dev/null 2>&1 & let i++; done; done &

--
Bye
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