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Displaying certain text in a msg.

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# 1  
Old 10-01-2012
Power Displaying certain text in a msg.
I have a requirement to display a part of an html response that my application gets. The response looks like this:
Code:
<html><a href='com.aprisma.spectrum.app.sd.client.SDHyperlinkHandler' sdTicketHandle='cr:419900' ocAlarmId='506618ea-f013-102d-02a7-0050569d7aa8' ticketUrl='http://lpv-casdwbdv01:8080/CAisd/pdmweb.exe?OP=SHOW_DETAIL+FACTORY=iss+PERSID=cr:419900'>Request/Incident 20056</a></html>

The part of the message I need to pull out is: "Request/Incident 20056"
where "20056" will change with every incoming message.

Is there a way to display all text between the > which is right before the R in Request and the < which is after the last digit of the number?

I have tried to do this:
Code:
SDMT=$SANM_0X12022
echo $SDMT | cut -f3 -d'>'

but my output looks like this:
Code:
Request/Incident 20056</a

I've tried everything I know.

Please helpSmilie
# 2  
Old 10-01-2012
Assumed the "Request/Incident" is always a fixed part of the msg, this should work:
Code:
awk '{TMP=substr($0,index($0,"Request/Incident")); print substr(TMP,1,index(TMP,"<")-1)}' file
Request/Incident 20056

This User Gave Thanks to RudiC For This Post:
dlundwall
# 3  
Old 10-01-2012
One Modification
The code that you sent worked perfectly!!! Thanks!!!

My only other question is, How would I bring JUST THE NUMBER in? So instead of the output:
Code:
Request/Incident 20085

I would like simply:
Code:
20085

MANY THANKS!@!
# 4  
Old 10-01-2012
Code:
awk '{TMP=substr($0,index($0,"Request/Incident")); print substr(TMP,18,index(TMP,"<")-18)}' file
20056

or
Code:
awk '{TMP=substr($0,index($0,"Request/Incident")+17); print substr(TMP,1,index(TMP,"<")-1)}' file

This User Gave Thanks to RudiC For This Post:
dlundwall
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