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Need regex shell script to remove text from file

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# 1  
Old 09-29-2012
Need regex shell script to remove text from file
Hello
I am trying to remove a line like <?php /*versio:2.05*/if (!defined('determinator')){ content goes here}?>
Now i want to scan all php file and remove that above line. I already write it but not working.
Code:
#!/bin/bash
find . -name '*.php' -exec grep -q determinator {} \; -print -exec perl -pi -w -e 's/\<\?php \/*versio:2.05;*/ if \(\!defined\(\$determinator.*\?\>//g' {} \;

Moderator's Comments:
Mod Comment Please use code tags

Can somebody help to solve that.

Thanks
Last edited by jim mcnamara; 09-29-2012 at 08:44 PM..
# 2  
Old 09-29-2012
Code:
find . -name "*.php" -exec grep -q determinator {} \; -print -exec perl -pe 's#<\?php /\*versio:2\.05\*/if \(\!defined\(\$determinator\)\)\{.*?\}\?>##g' {} \;

# 3  
Old 09-30-2012
Or perhaps more readably:
Code:
find . -name '*.php' | while read file ; do
   perl -pi -e 's...' $file
done

Last edited by mirni; 09-30-2012 at 03:53 AM.. Reason: fixed -pie
# 4  
Old 09-30-2012
Shouldn't perl -pie be perl -pi -e?
This User Gave Thanks to elixir_sinari For This Post:
mirni
# 5  
Old 09-30-2012
Yes, thanks. As you can probably tell, my perl skills are not very developed... :-\
# 6  
Old 09-30-2012
Hi balajesuri

Thank you for your reply.

I run the code you provided
Code:
find . -name "*.php" -exec grep -q determinator {} \; -print -exec perl  -pe 's#<\?php /\*versio:2\.05\*/if \(\!defined\(\$determinator\)\)\{.*?\}\?>##g' {} \;

But it just print me the entire file code

I want to update the file and remove the code i.e /*versio:2.05*/if (!defined('determinator')){ full content }
Last edited by Franklin52; 09-30-2012 at 05:57 PM.. Reason: Please use code tags
# 7  
Old 09-30-2012
@devp: Please include the option -i to perl code.

...-exec perl -i -pe 's....
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