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Extract first file only from ls command

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# 1  
Old 07-13-2005
Extract first file only from ls command
I need help in extracting first file only from an ls command
and store it in a local variable
I thought using awk we could build something - not very
familiar how to do it

Something like
ls -t $search_string and store the resultant
first file alone into a local variable ( as my result will have
multiple files )

Please help.
Thank you very much.
# 2  
Old 07-13-2005
Try
ls -t $searchstring | head -n 1 | read fileyouwant

or
fileyouwant=$(ls -t $searchstring | head -n 1)

I am using ksh.

If you create a script around it, use the normal #!/bin/ksh first line.

Greetings, William.
# 3  
Old 07-13-2005
with bash, you can also use

var=( $(ls) ) # var is an array witch contain the result of ls
echo ${var[0]}
# 4  
Old 07-14-2005
Bug ls -1t
try this

ls -1t|head -n 1

this should give you the output u want. Smilie
# 5  
Old 07-26-2005
Thanks for all of you who took time and answered.
>>>> fileyouwant=$(ls -t $searchstring | head -n 1) - It worked.

Thank you agin
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