I am trying to assign a value from the command to a dynamic variable. But I am not getting the desired output.. I am sure something is wrong so i need experts advise.
There will be multiple files like /var/tmp/server_1, /var/tmp/server_2, /var/tmp/server_3, having different server names in each file
The script below does read the file one by one, but i am finding the hard part in assigning the grep output to the dynamic variable SERVERS_${i}.
Eventually, i wanted to see the output
Server names in SERVERS_1: ssp01 ssp02 ssp03 ssp04
Server names in SERVERS_2: ssp05 ssp06 ssp07
Server names in SERVERS_3: ssp08 ssp09
If you want to assing values to variables (better: to elements of an array), you can do like that (in GNUlinux/bash):
If you want to print to screen the servers names, then:
--
Bye
Thanks Pamu.. I got the below output adding tr so i added export in front of it
./test: line 6: SERVERS_1=ssp01 ssp02 ssp03 ssp04 : command not found
_1
./test: line 6: SERVERS_2=ssp05 ssp06 ssp07 : command not found
_2
./test: line 6: SERVERS_3=ssp08 ssp09 : command not found
_3
However, i am getting the following result doing echo "${SERVERS}_${i}"
In the else of the main if condition .
else
set lnk = $(readlink -f <path> | cut -d '/' -f7)
echo "$lnk"
if ]
When I run the above on command line , the execution seems to be fine and I get the desired output. But when I try to assign it to a variable within a loop... (12 Replies)
Hi
iam new to shell scripting
how to declare variables as redshift query and I have to compare two counts by using if condition .
ex:count=select count(*) from prd;
select count(*) from prd;
select count(*) from tag;
can any one help me .
Please use CODE tags when displaying... (1 Reply)
Hi guys,
Is there a way to assign curent time to PS4 variable in ksh. My goal is to have each line produced by 'set -x' command to have a time stamp.
Here is my code:
$cat test
#!/usr/bin/ksh
export PS4="`date` "
set -x
echo "TRACE LINE ONE"
echo "I WILL SLEEP FOR 10 SEC"
sleep 10... (2 Replies)
Code
set -x
STATUS="0"
echo $STATUS
for i in `ls -ltr Report*|awk '{ print $9 }'`
do
if
then
flg = "`head -1 "$i" |cut -c 31-33`"
echo `head -1 "$i" |cut -c 31-33`
echo $flg
if
then
echo "having Fun"
STATUS="2"
else
echo "no Fun"
fi
fi (2 Replies)
Greetings folks,
I am trying to assign the output of a dscl command (contains name<spaces>id) to a variable as an array. Currently I am piping the output into a tmp file, then reading the tmp file into an array, then parsing the array. I would like to bypass creating the tmp file portion of... (6 Replies)
greetings all,
I am have a heck of a time trying to accomplish a very simple thing. I have an array of "shortname<spaces>id" created from a dscl output. I want to assign shortname=word1 and id=word2. I have tried
shortname=$(${textArray} | awk '{print $1}') - and get 'awk : cannot open... (3 Replies)
Hi ,
I would like to assign command (with pipe) output to a variable. The code is as follows. The goal of the code is to get the last folder folder with a particular name pattern.
myDate=`ls | grep 2009 | tail -1`
echo "myDate=" $myDate
However, in the presence of the pipe, the code... (3 Replies)
Hi,
I work in ksh88.
I have an interective script which prompts the user for the input and returns numeric value depending on the input provided. I need to call this script inside another script and then assign the resulting output the the variable.
The call like that A=`my script` obviously... (6 Replies)
Hi,
I am giving a grep command, and i am getting the output. i want to store it in a variable
for eg
a = grep '12345' /dir/1/2/log.txt ( the output is number)
b= grep 'basic' /dir/1/2/log1.txt (in this case the output is character)
so how to assign the output of grep to a variable
... (1 Reply)