Shell Programming and Scripting

I'm using solaris 10

Scenario as follows

I have a logfile with 2 columns:
column 1 = source directory + filename
column 2 = destination directory + filename

Using cron, my script polls for new files and adds them to the logfile ($ELOG) as described above. Using sed, the distination directory is created by changing 1 one the sub-directory locations

I'm trying to use awk to parse the file:
- encrypt the file
- copies the file to the destination folder

...
...

Code:

cat $ELOG | while read line;
do
   echo $line | awk '{print "ENCRYPT "$1" " print "<password>"}' | sh
   echo $line | awk '{print "cp "$1" "$2}' | sh

done

(ENCRYPT is a 3rd party executable file)

When I run the shell script, I get the following errors:

Code:

awk: syntax error near line 1
awk: illegal statement near line 1
awk: syntax error near line 1
awk: illegal statement near line 1
awk: syntax error near line 1
awk: illegal statement near line 1
awk: syntax error near line 1
awk: illegal statement near line 1

__________________

Can you help advise where/what I am doing wrong. Equally, if there is a smarter way of completig this task, that would be great too

Thanks in advance

David

Moderator's Comments:

Please use code tags next time for your code and data.

You are missing a semicolon before the second print statement.

use 'nawk' on Solaris...

Code:

nawk '{print "ENCRYPT", $1 ORS "<password>" ORS "cp",$1, $2}' "${ELOG}" | sh