10 More Discussions You Might Find Interesting
1. UNIX for Advanced & Expert Users
I have a below syntax its working fine...
var12=$(ps -ef | grep apache | awk '{print $2,$4}')
Im getting expected output as below:
printf "%b\n" "${VAR12}"
dell 123
dell 456
dell 457
Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies
2. UNIX for Dummies Questions & Answers
Hi,
I want to pass value of a variable track_line which is the line number to sed. Sed should print the lines starting from track_line till the last
line of the file. I tried the below command but it is not working.
sed -n '${track_line},$p' latest_log_file
I tried using the below too but... (1 Reply)
Discussion started by: nitinupadhyaya8
1 Replies
3. Shell Programming and Scripting
Stumped with the formatting of the awk output when used with variables, e.g.:
awk -F, 'BEGIN {OFS=","} print {$2,$3,$4}' $infile1
produces the desired output (with rows), but when echoing the variable below, the output is one continuous line
var1=$(awk -F, 'BEGIN {OFS=","} print... (4 Replies)
Discussion started by: ux4me
4 Replies
4. Shell Programming and Scripting
I have a variable $WORDS that contains a string
Then i want to use sed to break it up.
echo $WORDS | sed 's// /g'
I tried setting this as a variable by doing
WORDS2=`echo $WORDS | sed 's// /g'`
But when i do this it does not return me to the prompt properly
ie.
jmpprd-v1>
jmpprd-v1>... (4 Replies)
Discussion started by: nitrobass24
4 Replies
5. Shell Programming and Scripting
Hi,
I have a problem with passing a echo output into a variable in bash
file='1990.tar'
NAME='echo $file | cut -d '.' -f1';
echo $NAME
the result is
echo $file | cut -d . -f1
however with this one,#!/bin/bash
file='1990.tar'
echo $file | cut -d '.' -f1
the result is what I... (2 Replies)
Discussion started by: 1988PF
2 Replies
6. Shell Programming and Scripting
Hi,
I'm new here so I want to say hello to everyone first!
I searched google and this forum for a similar problem, but wasn't successful
#! /bin/bash
I'm trying to output (echo) n lines of a text file to the screen (later into another file).
But I have problem with the sed command, it won't... (1 Reply)
Discussion started by: studiologe
1 Replies
7. Shell Programming and Scripting
Hi All,
Hope someone can advise here as I have been struggling to find a syntax that works here. I have tried a stack of combination I have seed in the forums but I think because I have needed to use "" and `` in the statments another method is found.
I am reading in lines with the following... (1 Reply)
Discussion started by: nkwilliams
1 Replies
8. Shell Programming and Scripting
Dear All,
I want to print a file.
First I tried with this
sed '2q;d' filename
it worked. But when i put following it is not working
x=2;
sed '$xq;d' filename
Would any one suggest how to pass the variable? (7 Replies)
Discussion started by: saifurshaon
7 Replies
9. Shell Programming and Scripting
Hi,
In normal shell scripting, how do you pass the output of a command to a variable, instead of a file and be able to use it later?
The code is:
#!/bin/bash
who | cut -d" " -f1 > onlineusers
Instead of passing the output of the above command to the file called 'onlineusers'... (1 Reply)
Discussion started by: Furqan_79
1 Replies
10. Shell Programming and Scripting
I m trying to pass variable to sed.
export var=140920060731
sed -e '/$var/d' file
but no luch so far..? any body has any idea abt it
Is there any way to pass variable to SED?
Thanks ,
Manish (2 Replies)
Discussion started by: Manish Jha
2 Replies