Shell Programming and Scripting

Writing a ksh script. If someone starts a process with:
test.ksh > date.log

How can I grab 'date.log' name as a variable in test.ksh?

I need to get the 'date.log' name (not the contents) as a variable...without entering something like 'test.ksh date.log > date.log'

I guess I don't understand fully..

The redirection "name" is known only to the calling shell. test.ksh doesn't know about it at all. You will have to use either lsof or fuser to find out who has what file open.
Even then, I don't see any easy answer.

My real question is: if you were able to get it, what would you do with it?

Reason: test.ksh calls many other ksh files, that outputs their own condition codes. I need to be able to go through the log and look for bad condition codes that the called ksh files put out.

I'm not really looking for a stderr, since the ksh scripts put their own errors out.

I tried lsof, but since I'm not an admin, can't mess with the bin. I'll look into the fuser idea.

OK...nothing yet.

How about getting the stdout content as a variable...so I can hit it like that, or a way of copying during the process?

the script/program doesn't have access to the name of the file you are redirecting its output to. I suppose you can pass the file as a parameter to the script and then redirect all output to the passed in filename manually in the script.