Shell Programming and Scripting

nopes. that doesnt give me the output..basically what I am trying is using the first command I will check the existence of the directory by the outputstring1 and if present I will create a directory with the value of outputstring2

I guess what you have asked and what you want to achieve are two diff things command which i gave will get u the file names the way you wanted but how u wanna use that is completely at your stake..

If I get it right, you could do something like this

Referencing solution from #6,

Code:

for file in *.jar
do
 outstring1=$(echo "$file" | awk -F"[_.]" '{print $1,$2,$3}' OFS=_)
 outstring2=$(echo "$file" | awk -F"[_.]" '{print $(NF-1)}') 
done

Efficiency is highly depends on what you actually trying to achieve. It's possible that everything could be done in single commands without so-many external calls/pipes.
Please post your requirements in details with expected input and output sample.

basically, I have tens of files like the below:
$ls -1 *.jar
antispam_live_dec_20120727.jar
credit_transfer_live_bln_20120711.jar
credit_transfer_live_bln_20120711_1.jar
credit_transfer_live_bln_20120712.jar
credit_transfer_live_bln_20120712_1.jar
credit_transfer_live_bln_20120713.jar
credit_transfer_live_bln_20120713_1.jar
credit_transfer_live_bln_20120714.jar
credit_transfer_live_bln_20120714_1.jar
credit_transfer_live_bln_20120715.jar
credit_transfer_live_bln_20120715_1.jar
credit_transfer_live_bln_20120716.jar
credit_transfer_live_bln_20120716_1.jar
credit_transfer_live_bln_20120717.jar
credit_transfer_live_bln_20120717_1.jar
credit_transfer_live_bln_20120718.jar
credit_transfer_live_bln_20120718_1.jar
credit_transfer_live_bln_20120719.jar
credit_transfer_live_bln_20120719_1.jar
credit_transfer_live_bln_20120720.jar
credit_transfer_live_bln_20120720_1.jar
credit_transfer_live_bln_20120721.jar
credit_transfer_live_bln_20120721_1.jar
credit_transfer_live_bln_20120722.jar
credit_transfer_live_bln_20120722_1.jar
credit_transfer_live_bln_20120723.jar
credit_transfer_live_bln_20120723_1.jar
credit_transfer_live_bln_20120724.jar
credit_transfer_live_bln_20120724_1.jar
credit_transfer_live_bln_20120725.jar
credit_transfer_live_bln_20120725_1.jar
credit_transfer_live_bln_20120726.jar
ericsson_msc_live_bln_central1_20120725_1.jar
ericsson_msc_live_bln_central1_20120726.jar
ericsson_msc_live_bln_central1_20120726_1.jar
ericsson_msc_live_bln_central1_20120727.jar
ericsson_msc_live_bln_central1_20120727_1.jar
ericsson_msc_live_bln_central1_20120728.jar

......

what i want is:

1 to extract xx_xx_live from the string

2 store it in a variable A

3 check whether a directory of the same variable is created or not, if not the create it, and then go inside

4 extract the date part from the original string, that would be the following part: (credit_transfer_live_bln_20120726.jar) and store it in a variable B

5 check if a directory of same date as B is present under A or not, if not, then create it and move the original string file under that date.


If it helps, I can provide the whole list of file names

Thanks a lot everyone

Code:

#!/bin/ksh

## Operate on .jar files in the current directory.
for filename in *.jar
do
  ## Extract the directory name and date using regular expressions.
  dirname=$( print "$filename" | sed -n "s/^\(.*_live\).*/\1/p" )
  dirdate=$( print "$filename" | sed -n "s/.*_\([0-9]\{8\}.*\).jar$/\1/p" )

  ## If directory does not exist, create it.
  if [[ ! -d "$dirname" ]]; then
    mkdir $dirname
  fi

  ## Directory exists so test for date directory.
  if [[ ! -d "$dirname/$dirdate" ]]; then
    mkdir "$dirname/$dirdate"
  fi

  ## date dir exists so move file.
  mv "$filename" "$dirname/$dirdate"

done

exit 0

@gary_w

i tried out the individual sed expressions on the command line just to see the output and here is what I am getting the for the date part:

$for i in `ls -1 *.jar`;do echo $i|sed -n "s/.*_\([0-9]*\).jar$/\1/p" ;done
20120727
20120711
1
20120712
1
20120713
1
20120714
1
20120715
1
20120716
1
20120717
1
20120718
1
20120719
1
20120720
1
20120721
1
20120722
1
20120723
1
20120724
1
20120725
1
20120726
1
20120727
1
20120728
1
20120729
1
20120730
1
20120731
1
20120801
1
20120802
1
20120803
20120804
1
20120805
1
20120806
20120807
1
20120808
1
20120809
20120721
20120729
20120801
20120804
20120711
1
20120712
1
20120713

Check out the amended version that allows for the different naming convention.

Code:

sed -n "s/.*_\([0-9]\{8\}.*\).jar$/\1/p"