Shell Programming and Scripting

All,

i am comparing the output of one command to a numberic

Code:

if [[ `cat $ORATAB | grep ^+ASM | wc -l` = 1 ]]

but my problem is the output of follwoing is but but has some leading columns. I don't have any problme in LINUX and HP-UX. But only in AIX i am getting the leading spaces. I have developed my script on LINUX but when i try to run it fails because of this.

Code:

cat $ORATAB | grep ^+ASM | wc -l

o/p:
     1   -->  some leading spaces.

I am comparing like above one in many places so what will be the best option without assign the command output to a variable and compare it with another variable.

i.e Is there any way i can directly compare the o/p of command to a certain values in AIX ?

-Thanks,

what is output of this..?

Code:

cat $ORATAB | grep ^+ASM

Code:

cat $ORATAB | grep ^+ASM

o/p:
+ASM1:/u01/app/product/11202/grid:N           # line added by Agent

I need to compare the count

Code:

cat $ORATAB | grep ^+ASM | wc -l

please replace that by:

Code:

grep -c '^+ASM' $ORATAB

Hi rcc50886,
You said (correctly) that you want to compare numeric values, but the test operator you're using is for string comparisons. If you had changed your original code from:

Code:

if [[ `cat $ORATAB | grep ^+ASM | wc -l` = 1 ]]

to:

Code:

if [[ `cat $ORATAB | grep ^+ASM | wc -l` -eq 1 ]]

it would have done what you wanted.

As delugeag suggested:

Code:

if [[ `grep -c '^+ASM' $ORATAB` -eq 1 ]]

would be much more efficient.

It doesn't make any difference in this example, but quoting rules can get tricky inside `...`; using $( ... ) instead will frequently make your job much easier.