Shell Programming and Scripting

Try this..

Code:

$ DATE=`date +'%y%m%d'`
$ echo $DATE
120911

or another one

Code:

$ DATE=$(date +'%y%m%d')
$ echo $DATE
120911

Tried both methods, using brackets does seem to make the date command work however the TZ changes don't apply to it so its just outputs todays date

Hi JayJay02,

Can you try the below command?

Code:

DATE=`TZ=GMT-168 date +%y%m%d`

This yielded me

Code:

sirahu@sirahu-dt037:~$ DATE=`TZ=GMT-168 date +%y%m%d` ;echo $DATE
120912

where

Code:

sirahu@sirahu-dt037:~$ date
Tue Sep 11 17:25:45 IST 2012

All of the above just give todays date, I need it to be seven days previous

If you have FreeBSD try

Code:

date -v-7d +"%y%m%d"

Adjust the format to what you want.

Sorry I run Solaris, so the above won't work, thats for the input though

Ok. When I read through this thread I get a feeling that you perhaps haven't tried all different suggestions exactly as they are typed, or?
Please run this command and post exactly the result/error message:

Code:

date -d "7 days ago"

On my system it doesn't work with the suggestion with TZ=TZ+168..., but it seems to work with:

Code:

TZ=CEST+167 date

BUT the limit seems to be 167 hours, 1 hour less than 7 days. "CEST" is the local timezone for my server, you will see yours if you just do date, the characters before the year.

For me it also works with using seconds for 7 days:

Code:

date -r $(($(date +%s) - 604800))

For all these alternatives you can add the format you want at the end of the line, e.g. +"%Y-%m-%d"

Perhaps you also should read this:
https://www.unix.com/answers-frequent...rithmetic.html