Shell Programming and Scripting

Hi to all,

I'm here again, cause I need your help to solve another issue for me.

I have some files that have this name format: date_filename.csv
In my shell I must rename each file removing the date so that the file name is filename.csv
To do this I use this command:

Code:

fnames=`ls ${fname}| awk '{ FS = "_*" } ; { print $2 }'`

where fname contain, for example, 20120906_TESTFILE.csv
In this case it works correctly and return only the name TESTFILE.csv

Unfortunately in the file we receive from external systems there are some file that have in the name the '_' so some file are in this format:

Code:

20120906_TEST_FILE.csv

In this case the awk will return only TEST without extension (instead of TEST_FILE.csv).
In wich way I can obtain the desired result?????
I think that the solution is very simply for us but for me is a big issue
Thanks to all, in advance.
Bye.

Moderator's Comments:

Please use code tags next time for your code and data.

awk is not needed here. See this:

Code:

fname='20120906_TESTFILE.csv'
echo ${fname#*_}
TESTFILE.csv

fname='20120906_TEST_FILE.csv'
echo ${fname#*_}
TEST_FILE.csv

Thanks, I thinked it was very simply but not so simply!!!!

:-))