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Problems with awk printf, formatted output

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# 15  
Old 10-01-2012
@ Pamu & @ all

The above code works fine, but instead of hard coding can i use thea variable ?
# 16  
Old 10-01-2012
Quote:
Originally Posted by selvankj
but instead of hard coding can i use thea variable ?
try this - for using variables in awk...
Code:
awk -v FV="$first_var" -v SV="$second_var" '{ print FV,SV}' file

# 17  
Old 10-04-2012
@ Pamu

can we have a 'OR' conditon in awk ?? like the below
Code:
 
nawk -F, '$1=="3" && $4=="06" && $6=="C990" && ($9="89" || $9="90") {OFS=FS; if($2=="111") {$2="6H8"}.....

# 18  
Old 10-04-2012
Quote:
Originally Posted by selvankj
@ Pamu

can we have a 'OR' conditon in awk ?? like the below
Code:
 
nawk -F, '$1=="3" && $4=="06" && $6=="C990" && ($9=="89" || $9=="90") {OFS=FS; if($2=="111") {$2=="6H8"}.....

Yes. We can use OR in awk... like you have mentioned above..Smilie

like..
Code:
nawk -v VM="4" '(NR == VM || $0 > 4) && NR < 6 {print $0 }' file

# 19  
Old 10-04-2012
Thank you Pamu

But when i use more than one OR , i do not get expected results

Code:
 
nawk -F, '$1=="3" && $4=="06" && $6=="C990" && ( $9="6H8" || $9="6H9" || $9="6R8" )

# 20  
Old 10-04-2012
try using double ==

using single = sign it assigns the value to the variable..

try this...
Quote:
Originally Posted by selvankj
Code:
 
nawk -F, '$1=="3" && $4=="06" && $6=="C990" && ( $9=="6H8" || $9=="6H9" || $9=="6R8" )
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