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[Solved] Changing 0 to 1 and 1 to 0

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# 1  
Old 09-02-2012
[Solved] Changing 0 to 1 and 1 to 0
Hi

I have an expression that returns 1 if a text is found and 0 if its not found.
I need it the other way around. 0 of found and 1 if its not found

Code:
echo $((`cat /var/log/system1/output.html | grep aligment | head -n1 | wc -l`))

Is this possible without doing an if/then/else, just with math (bolean) in same line?

Edit
"grep -q" worked great
Last edited by Jotne; 09-02-2012 at 09:06 AM..
# 2  
Old 09-02-2012
Try this:
Code:
grep -q alignment /var/log/system1/output.html && echo 0 || echo 1

--
Bye
This User Gave Thanks to Lem For This Post:
Jotne
# 3  
Old 09-02-2012
You got Useless Use of Cat AwardSmilie

With awk...

Code:
awk '/search_string/ {{s="0";next}}END{if(s) {print s}else{print "1"}}' file

This User Gave Thanks to pamu For This Post:
Jotne
# 4  
Old 09-02-2012
Code:
grep -q alignment /var/log/system1/output.html; echo $?

# 5  
Old 09-02-2012
Quote:
Originally Posted by RudiC
Code:
grep -q alignment /var/log/system1/output.html; echo $?

Hi Rudic,

$? status is not always 0 or 1;

Please check here..

Regards,
pamuSmilie
# 6  
Old 09-02-2012
Thanks, pamu, you're absolutely right! If using bash, replace the echo $? by
Code:
 echo $(( $??1:0 ))

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