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passing argument from one function to another

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# 22  
Old 09-01-2012
Quote:
Originally Posted by pamu
don't use PATH as variable
Smilie ..what an idiot I was not to notice that...rectified in my post..
thanks.
# 23  
Old 09-01-2012
Quote:
Originally Posted by elixir_sinari
Smilie ..what an idiot I was not to notice that...rectified in my post..
thanks.
lol..applicable for both of us, i guess..Smilie

Thanks pamu..Smilie
# 24  
Old 09-03-2012
Hi,
I would like to modify the script [1].
Change data*.list to data1.list in the line below, it did not work.
Actually, to begin the script should read data1.list.

Code:
     { rm $CARD; sed -e "s/data*/data1/g" > $CARD; } < $CARD

thanks

[1]
Code:
 #For Submiting the batchjobs                                                                                                                                           
SubmitBatchJob () {
    max=$FileId
    for (( k=0; k < $max ; ++k )) ;
      do
      echo "SHELL JOB ================ $k =============="
      if [ $k == 0 ]; then
          source $SCRIPT
      else
          if [ $k > 0 ]; then
              { rm $CARD; sed -e "s/data$k/data$((k+1))/g" > $CARD; } < $CARD
              source $SCRIPT
              echo "SUCCESFULLY DONE.."
          else
              if [ $k = $max ]; then
                  echo "TERMINATES.."
              fi
          fi
      fi
    done
}

# 25  
Old 09-03-2012
Bug Try this...
Code:
 { rm $CARD; sed -e 's/data'$k'/data'$((k+1))'/g' > $CARD; } < $CARD

# 26  
Old 09-03-2012
Hi,
Completely stuck..Not working,
With the given script:

I have checked beofore that total no of files present in the given PATHNAME[] are 1021, whereas the FileName has some 3061 files.. duplication of files are happening..Smilie Smilie

Kindly reply,

Code:
PATHNAME[1]="/eos/uscms/store/user/pooja04//analysis2012/525/data/doubleele/2012/datav1/"
PATHNAME[2]="/eos/uscms/store/user/pooja04//analysis2012/525/data/doubleele/2012/datav4/"

#To Copy the Files Inforamtion from the Destination Folder                                                                                                             
CopyFilesInfo() {
    for FileNameIndx in "${PATHNAME[@]}"
      do
      ls -ltr "$FileNameIndx" | grep root | awk '{print string path $9}' string="$CONSTANT" path="$FileNameIndx"  >> "$FileName"
      echo "$FileNameIndx is copied"
    done
}

---------- Post updated at 02:19 AM ---------- Previous update was at 02:17 AM ----------

Quote:
Originally Posted by pamu
Code:
 { rm $CARD; sed -e 's/data'$k'/data'$((k+1))'/g' > $CARD; } < $CARD


Hi Pamu,
Many Thanks for the quick reply,
But I want the following:
initial data can have *data5.list* or *data25.list* or whatever the value. I would like to use *sed* to change it to *data1.list*.

pooja
# 27  
Old 09-03-2012
Hi,

FileName file will be having all the files from PATHNAME 1,2.. and so on
Check for both the paths.Smilie

Use back stick while you want use * as part of the string...

Code:
 echo "data*.list" | sed -e "s/data\*/data1/g"

# 28  
Old 09-03-2012
Quote:
Originally Posted by pamu
Hi,

FileName file will be having all the files from PATHNAME 1,2.. and so on
Check for both the paths.Smilie
Yes it has..definitely..!! But on top of it, it has duplication of those files as well..SmilieSmilie
Just checked..it duplicate the file name THRICE..Smilie
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