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How to replace with a special character in String

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# 1  
Old 08-23-2012
How to replace with a special character in String
Hi,

I am beginner to Shell Scripting.

I have a String like this "testabcdef", i need the first character as it is and the remaining character should be replaced by the the '*' character. e.g(t***********)

PLZ Suggest me.
# 2  
Old 08-23-2012
one way

Code:
 
$ echo "abcd234234234" | nawk -v FS="" '{a=substr($0,1,1);for(i=2;i<=length($0);i++)a=a"*"; print a}'
a************

# 3  
Old 08-23-2012
Slightly different, without a loop:
Code:
$ echo "abcd234234234"| awk '{c=$1; gsub(/[a-z0-9]/,"*"); $1=c; print; }' FS= OFS=
a************

This User Gave Thanks to zaxxon For This Post:
nanthagopal
# 4  
Old 08-23-2012
Quote:
Originally Posted by zaxxon
Slightly different, without a loop:
Code:
$ echo "abcd234234234"| awk '{c=$1; gsub(/[a-z0-9]/,"*"); $1=c; print; }' FS= OFS=
a************

Thank You for your Replay,

It's Working fine, but i am not able to store the result in a variable.
# 5  
Old 08-23-2012
Quote:
Originally Posted by nanthagopal
Thank You for your Replay,

It's Working fine, but i am not able to store the result in a variable.

Use this..

Code:
$ var=$(echo "abcd234234234"| awk '{c=$1; gsub(/[a-z0-9]/,"*"); $1=c; print; }' FS= OFS=)
$ echo $var
a************

# 6  
Old 08-23-2012
Only tested with bash (should work with ksh93):
Code:
x=abc; y=${x:1}; z=${x:0:1}${y//?/*}

Regards,
Alister
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