Shell Programming and Scripting

No, you can't. Use the other code.

Read from whatever file you want with <, or nothing at all by leaving it off completely.

So I've tried a lot different ways in capturing files not found for above command, no luck. can someone guide me in capturing for the files not found from the input file (i.e) ID.

In what way does it not work?

I have tried in the below way and have even tried with some find commands.

Code:

while read ID
do
        [ -f "/photos/${ID}.jpg" ] && echo "/photos/${ID}.jpg"
        [ -f "/photos/thumbnail/${ID}-tn.jpg" ] && echo "/photos/thumbnail/${ID}-tn.jpg"
done < ID >list_file 2>error_file

Yes, and in what way did they not work?

I can only get the info in the list_file and the error_file is empty. Am i doing it in the right way? Please correct me if i am wrong.

I don't think you're really looking at the code.

Code:

while read ID
do
        [ -f "/photos/${ID}.jpg" ] && echo "/photos/${ID}.jpg"
        [ -f "/photos/thumbnail/${ID}-tn.jpg" ] && echo "/photos/thumbnail/${ID}-tn.jpg"
done < ID >list_file 2>error_file

This is the code I told you not to use.

I don't know why you'd expect error_file to get anything inside it when all you're doing is echo's inside the loop. Read it -- there's no mv inside there.

I'm hoping the ID I highlighted blue is a valid filename. It's supposed to be the input file you're reading ID's from. If it's not, it's wrong.

Try this:

Code:

while read ID
do
        echo "${ID}.jpg"
        echo "thumbnail/${ID}-tn.jpg"
done < inputfile | xargs rm 2> errlog

I left off the 'rm' by accident. It must have been printing all the filenames, as xargs does when it isn't given a program to run. If you'd mentioned this, that would have helped discover the problem. But all you ever say is 'not working'...