awk get the row


 
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# 1  
Old 08-20-2012
awk get the row

Code:
somthing
somthing
A B C B F A B ....
1 2 3 4 5 6 7  ....
7 9 12 2 4 5 8

I want to get the row which is the same row as B.

Code:
This this the 
 
2 4 7 
9 2  8

# 2  
Old 08-20-2012
Code:
awk ' /^A/ {ok=1; 
                 for(i=1; i< NF ; i++) {arr[i]=($1=="B") ? arr[i]=1:arr[i]=0}
                 next
               }
               ok==1 { for(i=1; i< NF ; i++)  
                          {printf("%s", (arr[i]) ? $i: "" }  
                           printf("\n")
                        }' infile > outfile

# 3  
Old 08-20-2012
May I suggest two corrections:
($1=="B") should become ($i=="B") to really test every single column and
i< NF should become i<= NF to find the "B" even if it were the last item in the line. You also might want to print a blank to separate adjacent columns.
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