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Simple listing directory question

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# 1  
Old 08-17-2012
Simple listing directory question
I have a very basic question:
How do I list all the directories in the following order?
If I do
Code:
 ls -l

I get different results than I want to achieve.

Code:
dir.1
dir.2
dir.3
dir.4
dir.5
dir.6
dir.7
dir.8
dir.9
dir.10
dir.11
dir.12
dir.13
dir.14
dir.15
dir.16
dir.17
dir.18
dir.19
dir.20
dir.21
dir.22
dir.23
dir.24
dir.25
dir.26
dir.27
dir.28
dir.29
dir.30
dir.31

# 2  
Old 08-17-2012
use pipe
ls | sort

try using the above command....
# 3  
Old 08-17-2012
By default, ls sorts the listing in lexicographical order. To change that (for this particular case), use
Code:
ls dir*|sort -t. -k2n

# 4  
Old 08-17-2012
If you have a free hand in designing the naming convention, you could also fix the length of the numeric suffix, say to 5 digits with leading zeros, so:-
Code:
$ ls -1
dir.00001
dir.00002
dir.00003
dir.00004
dir.00005
dir.00006
dir.00007
dir.00008
dir.00009
dir.00010
dir.00011
dir.00012

It depends what you can define and what you are forced to use.



I hope that this helps.

Robin
Liverpool/Blackburn
# 5  
Old 08-17-2012
Quote:
Originally Posted by elixir_sinari
By default, ls sorts the listing in lexicographical order. To change that (for this particular case), use
Code:
ls dir*|sort -t. -k2n

That will attempt to sort the contents of multiple directories. You can use -d, but if there are very many directories, there could be a problem executing the command after the shell pathname expansion has generated a long list. grep would be a better solution.

Regards,
Alister
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