Shell Programming and Scripting

$ cat b22
373 164 92 62 20 131 94 12 129 111 95 154 37 15 447 25 7.4 135 77 122 32 92 70 57 37 42 72 17 13 97 40 41 53 22 80 71 29 87 23 31 273 6.2 12K 43 44 45 22 11 7.7 13 18 173 36 20 18 13 56 67 104 53 5.4 241 19 13 3.8 38 14 31 329 16 155 17 81 74 18 45 110 58 23 4.0 13 33 6.9 32 68 28 22 34 139 60 31 22 101 12 13 105 14 19 109 11 6.6 65 44 9.0 132 221 16 16 166 11 76 46 38 42 18 87 68 29 5.4 3.4 41 32 27 406 275 35 24 26 49 5.2 19 146 60 41 12 7.9 77 14 15 24 29 98 24 98 187 56 96 9.5 46 60 24 25 169 196 13 37 16 50 76 12 181 12 74 8.2 26 112 21 12 86 41 1.5 2.3 130 8.2 415 36 24 18 52 54 17 11 8.1 9.2 101 15 85 44 43 107 21 19 111 6.2 26 42 15 39 116 33 49 60 20 127 7.6 55 84 87 34 32 22 21 66 102 29 14 20 7.7 27 22 12 25 138 45 6.4 40 18 34 103 22 18 64 106 121 7.7 16 75 9.3 7.9 23 4.8 28 40 63 23 50 3.4 14 1.5 24 5.4 9.2 16 73 34 150 13 41 120 127 260 4.3 147 14 29

 
expr: non-numeric argument

 
-bash: let: a=1.2+2.8: syntax error: invalid arithmetic operator

 
$ $sum=0; for i in `cat b22`
> do
> sum=`echo "$sum + $i" | bc`
> done; echo $sum;

(standard_in) 1: parse error

 awk 'BEGIN { print ( 1.2 + 1.25 ) }'
2.45

awk '
BEGIN {FS=OFS=" "}
{
sum=0; n=0
for(i=1;i<=NF;i++)
     {sum+=$i; ++n}
     print "sum:"sum
}' temp_test

$sum=0; for i in `cat b22`
do
sum=`echo "$sum + $i" | bc`
done; echo $sum;

awk ' {	for (i=1; i<= NF; i++) sum+=$i }
END {print sum}' b22

tr ' ' '+' <b22|bc

sum=0
for i in $(<b22); do
    sum=$((sum + i))
done
echo $sum