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Shell Programming and Scripting

Extract file names from a file

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# 8  
Old 08-14-2012
For GNU sed version 4.2.1 this works using just one sed command:
Code:
sed  -n 's/d:/\n&/g; s/\.cfg/&\n/g; s/^\n*//g; /^d:/ P; D'

It surrounds the filenames (d:...cfg) with <newline> chars, eliminates multiple <newline>s at the beginning of the line, up to the next <newline> it prints out that part if starting with "d:" , and then deletes that part.
# 9  
Old 08-14-2012
Using any sed:
Code:
sed -n 'h
:again
g
s/\([[:alpha:]]:[^.]*\.cfg\).*/\1/
s/.*\([[:alpha:]]:[^.]*\.cfg\)/\1/p
g
s/[[:alpha:]]:[^.]*\.cfg//
h
t again' infile

And with awk:
Code:
awk '{while(match($0,/[[:alpha:]]:[^.]*\.cfg/))
{
 print substr($0,RSTART,RLENGTH)
 sub(/[[:alpha:]]:[^.]*\.cfg/,"")
}
}' infile

Last edited by elixir_sinari; 08-14-2012 at 06:00 AM..
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