Shell Programming and Scripting

I don't know what OS you are on, but an easy and ALWAYS working way to get the last modification date is to do an "ls -l".

Having said this, the following line should give you the desired result for a file (replace "<space>" with literal spaces and <filename> with the filename):

Code:

ls -l <filename> | sed 's/<space><space>*/<space>/g' | cut -d'<space>' -f6,7

This should give something like "Apr 14" or "Jun 22". Look at the output of "ls -l". First, the sed-statement reduces multiple occurences of spaces to exactly one each. Then "cut" is used to get out the fields 6 and 7 (-f6,7) using spaces as delimiters between fields (-d'<space>'). I describe this in detail because it is a very common way of extracting data from tabular input, you may want to experiment with it a little to really understand how it works.

To put the extracted data into your HTML file you will need this plus some HTML-Tags surrounding it, namely "<TD>" and "</TD>". The following should do the trick:

Code:

chFileDate="$( ls -l <filename>                  |\
               sed 's/<space><space>*/<space>/g' |\
               cut -d'<space>' -f6,7              \
             )"
print - "<TD> $chFileDate </TD>" | tee -a $HTMLFILE

Hope this helps

bakunin

it doesnt work

Code:

modiDate = "$( ls -al $PFAD$DR | sed 's/ */ /g* | cut -d ' ' -f6,7)"

i have Hp-Unix System

Yeah

I have solved this problem problem with

Code:

ls -al $PFAD$DR | awk '{printf("<TD>%s %s %s\n", $6, $7, $8)}' | tee -a $HTMLFILE

and now i need the german format of the date

it print's Feb 22 10:48

i want '17. Jan 2005'

how can i solve this one

try

Code:

ls -l --time-style="long-iso"
or
ls -l --time-style="+%e,%b %Y"

It works on gentoo 1.4.

It doesn't work, because you have written "cut -d ' '" instead of "cut -d' '", have forgotten a closing single quote on the sed-statement and put a (superfluous) asterisk there instead. On top you have replaced the two spaces in the matching string of the sed-script with one, which alters greatly what the script does. Instead of changing one or more spaces to exactly one space it changes zero or more spaces to exactly one space now.

Your awk solution is not really recommendable, because you call awk several times for every table row and perhaps nested in a loop to print several rows only to do a formatted print which can be done directly in the shell. Maybe your environment has enough unused computing power to allow for that, but in principle this is a waste of resources.

It may be that I'm old-fashioned, but I learned that a good solution is not one that works but one that works and is efficient and elegant. Computing power or any other resource should never be taken for granted and neither wasted if it could be conserved.

Ok, I'm already through ranting.....

bakunin

PS: to get the german Date switch your language environment to german oder "de_de". Having no HP-Ux-machine at hand i can point you only in the general direction, you should find this somewhere in the sam-menus in the user configuration.

bakunin

@r2007
I've tried this but when i execute it he say --time-style="long-iso" not found an the second example, too.

@bakunin
thank you for your opinion. I try your solution and if it works i apply it on code.