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Argument Problems with ncftpput

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# 8  
Old 08-08-2012
Quotes do not work that way. Instead of wondering why, just test what they actually do:

Code:
$ var="asdf"

$ echo '"$var"'

"$var"

$ echo "'$var'"

'asdf'

$ echo "$var"

asdf

$

Therefore, shell doesn't actually do what you think it does.

Putting variables in double-quotes is a good idea when you don't want them to split. Single quotes don't evaluate variables at all. And extra quotes inside double quotes don't get evaluated, just stick around.
# 9  
Old 08-10-2012
Quote:
Originally Posted by Corona688
Quotes do not work that way. Instead of wondering why, just test what they actually do:

Code:
$ var="asdf"

$ echo '"$var"'

"$var"

$ echo "'$var'"

'asdf'

$ echo "$var"

asdf

$

Therefore, shell doesn't actually do what you think it does.

Putting variables in double-quotes is a good idea when you don't want them to split. Single quotes don't evaluate variables at all. And extra quotes inside double quotes don't get evaluated, just stick around.
Okay, I understand now.

My code is now:
Code:
#/bin/bash

echo "Running command: ncftpput -R -u "$2" -p "$3" "$1" "$5" "$4""
ncftpput -R -u "$2" -p "$3" "$1" $5 $4

Code:
./ftpWebsite.sh '1.2.3.4' 'username.co.uk' 'pass.!pass' /var/www/vhosts/username.co.uk/httpdocs/ /public_html

This - WORKS! Smilie

Code:
./ftpWebsite.sh '1.2.3.4' 'username.co.uk' 'pass.!pass' /var/www/vhosts/username.co.uk/httpdocs/* /public_html

This however, doesn't, with the * to denote the contents of the folder, not the folder itself, it complains about not being able to change to a directory, and the "directory" it lists, is the first file in that folder... how do I use *?

Thanks in advance.

---------- Post updated 08-10-12 at 06:49 AM ---------- Previous update was 08-09-12 at 07:19 AM ----------

Sorry to bump, but I'm still having troubles with this script...could anybody point me in the right direction?
# 10  
Old 08-10-2012
The shell will expand that into a lot more than $4. You'd need to shift off 1-3, then use "$@"
# 11  
Old 08-10-2012
Sorry, I don't fully understand that. I know I'm coming across as wanting to be spoonfed Smilie

What do you mean by the shell will expand into more than $4? how do you 'shift off'? I understand $@ is all arguments separated with a space, but I am still unclear as to the rest.
# 12  
Old 08-10-2012
It means you could also end up with $5, $6, $7, ... depending on how many files * finds. You're not putting a literal * into ncftp, and if you did, it probably wouldn't work. It's the shell's job to turn * into filenames for you ahead of time.

You shift with the shift command. It works like this:

Code:
set -- a b c d e # Set $1=a, $2=b, $3=c, ... for example

echo $1 # Should print a

shift 2 # Get rid of the first two

echo $1 # should print c
echo $2 # should print d
echo $3 # should print e
echo "$@" # should print c d e

"$@", quotes and all, is a special operator which means "all arguments". So if you get rid of the first few arguments, you can feed "$@" into your FTP program and feed it all the arguments instead of hardcoding $1 $2 $3 $4 etc.
Last edited by Corona688; 08-10-2012 at 10:57 AM..
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