Login or Register to Ask a Question and Join Our Community


Shell Programming and Scripting

reg expression in perl

Login to Discuss or Reply to this Discussion in Our Community

 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting reg expression in perl
# 1  
Old 08-07-2012
reg expression in perl
./GEN_SCR.pl -f ${REP_PATH}/FUNCTIONAL/wide1c_1.0V/max/qor.rpt -o ${REP_PATH}/FUNCTIONAL/GEN2_wide1c_1.0V_max.csv



where GEN_SCR.pl is as below...i need to check whether max or min is coming in the argument to the script ...how to do this?
${REP_PATH}/FUNCTIONAL/wide1c_1.0V/max/qor.rpt
_______________________________________________________
!/usr/local/bin/perl
use Getopt::Std;
getopts (":f : o :");


< logic for max or min ?????>
___________________________________________________________
how to do this?
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

REG Expression

Need your help in creating regular expression for particular set. let say I have given two dates 20130623 to 20140625. I need to create regular for the dates which fall in between above two dates. (4 Replies)
Discussion started by: gvkumar25
4 Replies

2. Shell Programming and Scripting

Confusion with Reg expression

I want to make a REG Expression to validate the directory. my dirsample is below: /abc/abc/abc abc/abc/abc abc/abc/abc/ /abc/a bc/abc /a bc/abc/abc /abc/abc/a bc / abc/abc/abc /abc/ abc/abc /abc/.abc /.abc/abc / // /abc /.abc And my code is below: grep -E '^\/(+\/?)+$' dirsample (4 Replies)
Discussion started by: franksunnn
4 Replies

3. Shell Programming and Scripting

reg expression in perl

how to uniquely match each of the words seperated by / in perl ${REP_PATH}/FUNCTIONAL/wide1c_1.0V/max/qor.rpt https://www.unix.com/images/misc/progress.gif (5 Replies)
Discussion started by: dll_fpga
5 Replies

4. Shell Programming and Scripting

Reg expression

Please let me understand this reg expression (\s+')(.*)('\s+)(.)(.*)(\/.*)/) i have doubt in the below 2.I'm not understanding why back-tick used? (\s+') and ('\s+) (2 Replies)
Discussion started by: dll_fpga
2 Replies

5. Shell Programming and Scripting

awk reg expression

Hello, I have thousand of messages (HL7), I want to use awk to extract only the ones that have a particular value in pv1.18 Each record in the file is the whole HL7 message, ie. when I print $0 I get the whole message MSH EVN PID etc. ,there is an x0d between the segments. I would like to use a... (3 Replies)
Discussion started by: gio001
3 Replies

6. Shell Programming and Scripting

Python (startswith) reg expression

Hello together, Yesterday I have recieved the script in the forum which works well. This script should insert in the previous line, the line that starts with ";". I'd like this process to recur after any arbitrary sign unless there's a number as a sign at the beginning of a line. Actual... (14 Replies)
Discussion started by: research3
14 Replies

7. Shell Programming and Scripting

Reg expression For

HI system.sysUpTime.0 : Timeticks: (1519411311) 175 days, 20:35:13.11 From the above output i need only 175days in a perl script.. Please Help (2 Replies)
Discussion started by: Harikrishna
2 Replies

8. Shell Programming and Scripting

perl reg expression

I have regular expression like this ( replace + with \+) ($mod_server) = ($server =~ /\+/\\+/g); the above is failing with error . what's wrong with it . Thanks (1 Reply)
Discussion started by: talashil
1 Replies

9. UNIX for Dummies Questions & Answers

Help with Reg. Expression

I need help with this: Can any one tell me what does these below mean: 1. "\(.\).*") != '/' 2. sed 's+^\./++;s+/.*++' 3. sed "s+${f}/+ + Thanks in advance (7 Replies)
Discussion started by: moe2266
7 Replies

10. Shell Programming and Scripting

Command param subst to reg expression

I want to find out Row which starts with, the user specified details to a script. In general I know what command to be given. awk '$0~/^Vi/' BReject But I need to pass on $1 param of command line at the place of 'Vi'. I tried with -v subst=$1 awk -v subst=$1 '$0~/^subst/' BReject But it... (5 Replies)
Discussion started by: videsh77
5 Replies
Login or Register to Ask a Question

LEARN ABOUT DEBIAN

gedcom::grammar

Gedcom::Grammar(3pm)					User Contributed Perl Documentation				      Gedcom::Grammar(3pm)

NAME

       Gedcom::Grammar - a module to manipulate Gedcom grammars

       Version 1.16 - 24th April 2009

SYNOPSIS

	 use Gedcom::Grammar;

	 my $st = $grammar->structure("GEDCOM");
	 my @sgr = $grammar->item("DATE");
	 my @items = $grammar->valid_items;
	 my $min = $grammar->min;
	 my $max = $grammar->max;
	 my @items = $grammar->items;

DESCRIPTION

       A selection of subroutines to handle the grammar of a gedcom file.

       Derived from Gedcom::Item.

HASH MEMBERS

       Some of the more important hash members are:

   $grammar->{top}
       The top of the grammar tree.

   $grammar->{top}{structures}
       A reference to a hash mapping the names of all structures to the grammar objects.

METHODS

   structures
	 my $st = $grammar->structure("GEDCOM");

       Return the grammar item of the specified structure, if it exists, or undef.

   item
	 my @sgr = $grammar->item("DATE");

       Return a list of the possible grammar items of the specified sub-item, if it exists.

   min
	 my $min = $grammar->min;

       Return the minimum permissible number of $grammar items

   max
	 my $max = $grammar->max;

       Return the maximum permissible number of $grammar items

   items
	 my @items = $grammar->items;

       Return a list of tags of the grammar's sub-items

   valid_items
	 my @items = $grammar->valid_items;

       Return a hash detailing all the valid sub-items of the grammar item.  The key is the tag of the sub-item and the value is an array of
       hashes with three members:

	 grammar => the sub-item grammar
	 min	 => the minimum permissible number of these sub-items
	 max	 => the maximum permissible number of these sub-items

perl v5.14.2							    2012-04-12						      Gedcom::Grammar(3pm)