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a cut-command or special format pattern in awk

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# 1  
Old 08-06-2012
a cut-command or special format pattern in awk
Hi

i read data with awk,
Code:
01.07.2012	00:10	227.72	247.50	1.227	1.727	17.273
01.07.2012	00:20	237.12	221.19	2.108	2.548	17.367
01.07.2012	00:30	230.38	230.34	3.216	3.755	17.412
01.07.2012	00:40	243.18	242.91	4.662	5.172	17.328
01.07.2012	00:50	245.58	245.41	5.179	5.721	17.128
01.07.2012	01:00	256.63	253.30	5.002	5.711	16.980
01.07.2012	01:10	263.29	257.95	5.208	5.860	16.746
01.07.2012	01:20	262.18	258.82	5.529	6.091	16.477

and i want to achieve an output, especially for the timestamp 07/01/12-hh:mm
Code:
...
awk '{printf("%02d/%02d/%2d-%02d:%02d\t%.2f\t%.2f\t%.3f\t%.3f\t%.3f\n",$2,$3,$1,$4,$5,$6,$7,$9,$10,$11)}' OFS='\t' $home/data.dat > $home/out.txt

Is there an parameter for awk '{printf( , where i can set the pattern for two-number-year?

Thanks in advance!
IMPe
# 2  
Old 08-06-2012
Code:
echo "2012" | awk '{printf "%02d\n", substr($0,2)}'
12

# 3  
Old 08-06-2012
Quote:
Originally Posted by in2nix4life
Code:
echo "2012" | awk '{printf "%02d\n", substr($0,2)}'
12

THANK YOU, it is working properly!
# 4  
Old 08-06-2012
Code:
awk '{split($1,a,".");$1=a[1]"/"a[2]"/"a[3]%100"-"$2;$2=""}1' OFS='\t' myFile

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