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Print a number up to last significant digit after decimal point

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# 1  
Old 08-04-2012
Print a number up to last significant digit after decimal point
I want to write/print a number through a shell script up to its last significant digit (LSD) after the decimal point.

Say,

x=10.00056000000000000

I want to print x as x=10.00056.


Note that x can be any thing so I cannot know the position of the LSD always.

Thanks.
# 2  
Old 08-04-2012
Try:
Code:
echo "$x" | sed 's/0*$//'

# 3  
Old 08-04-2012
Thanks a lot. It seems working. Is there an alternative way by using 'awk' as well?
# 4  
Old 08-04-2012
Code:
echo "$x" | awk '{sub("0*$","",$0)}1'

# 5  
Old 08-04-2012
Cool ! Thanks a lot. SmilieSmilie
# 6  
Old 08-04-2012
Why not just do it in the shell:
Code:
echo "${x%%*([0])}"

This should work in all of the common shells except csh.
# 7  
Old 08-04-2012
Wow ! That's cool too. Thanks Don too.

But there's a little problem. If x=10.0000, I get 10. , where I might expect 10.0

Can this be taken care too?
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