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Print a number up to last significant digit after decimal point

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Top Forums Shell Programming and Scripting Print a number up to last significant digit after decimal point
# 15  
Old 10-01-2012
Extension to the previous problem
What if I want to print x keeping 0 before the decimal point irrespective of the case x having the 0 already or not?

For example,

if x=0.0090, I should print 0.009

and also

if x=.0090, I should print 0.009

Thanks.
# 16  
Old 10-01-2012
try this..

Code:
$echo "0.0090" | awk '{sub("0*$","",$0);sub("\\.$",".0",$0);sub("^\\.","0.",$0)}1'
0.009


$ echo ".0090" | awk '{sub("0*$","",$0);sub("\\.$",".0",$0);sub("^\\.","0.",$0)}1'
0.009

# 17  
Old 10-01-2012
What's wrong with a simple print in numeric context?
Code:
echo "0.0090"|awk '{print $1+0}'
0.009

echo ".0090"|awk '{print $1+0}'
0.009
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