variable inside if bracket


 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting variable inside if bracket
# 1  
Old 08-02-2012
variable inside if bracket

Is this possible? The below code not working for me.
Code:
dir=mydir
 if [ -d /home/$mydir ]; then 
       echo "found /home/$mydir "
 else 
       echo "Not found /home/$mydir"
fi

---------- Post updated at 05:28 AM ---------- Previous update was at 05:25 AM ----------

Its working for me now
# 2  
Old 08-02-2012
It was no big problem I guess, but keep in mind to post your solution, when you found one.
This forum is for the benefit of all, not just you. Ok?!
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Remove bracket including text inside with sed

Hello, I could not remove brackets with text contents myfile: Please remove the bracket with text I wish to remove: I tried: sed 's/\//' myfile It gives: Please remove the bracket with text A1 I expect: Please remove the bracket with text Many thanks Boris (2 Replies)
Discussion started by: baris35
2 Replies

2. Shell Programming and Scripting

To print value for a $variable inside a $variable or file

Hi guys, I have a file "abc.dat" in below format: FILE_PATH||||$F_PATH TABLE_LIST||||a|b|c SYST_NM||||${SRC_SYST} Now I am trying to read the above file and want to print the value for above dollar variables F_PATH and SRC_SYST. The problem is it's reading the dollar variables as... (5 Replies)
Discussion started by: abcabc1103
5 Replies

3. Shell Programming and Scripting

Resolve variable inside another variable

Hello Everyone, I am trying to resolve a variable inside another variable.Let me go straight to the example. Input: Query=$Table_1 Join $Table_2 (Query itself is a variable here) Now for two different cases I am assigning different values to Table_1 and Table_2 Case 1:... (14 Replies)
Discussion started by: vinay4889
14 Replies

4. Shell Programming and Scripting

ksh, difference between double bracket and single bracket

Can somebody tell me the difference between double brackets and single brackets, when doing a test. I have always been acustomed to using single brackets and have not encountered any issues to date. Why would somebody use double brackets. Ie if ] vs if Thanks to... (2 Replies)
Discussion started by: BeefStu
2 Replies

5. Shell Programming and Scripting

evaluating a variable inside a variable

Hi there, i think im getting myself a little confused and need some help :wall: I am reading in a bunch of variables to my script from an external file and need to validate that a value has been set for each so if you can imagine, the user is required to pass in 4 values... (3 Replies)
Discussion started by: rethink
3 Replies

6. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

7. Shell Programming and Scripting

variable inside variable inside loop headache

Hi Gurus I have a file called /tmp/CMDB which looks like this serial: 0623AN1208 hostname: server1 model: x4100 assetID: 1234 I am writing a for loop that will go through this file line by line creating a variable of itself. Using the first iteration of the loop (i.e. the first line) as... (6 Replies)
Discussion started by: hcclnoodles
6 Replies

8. UNIX for Dummies Questions & Answers

passing a variable inside a variable to a function

I would like to know how to pass a variable inside a variable to a function. sample code below -------------- for x in 1 9 do check_null $C$x ##call function to check if the value is null if then echo "line number:$var_cnt,... (2 Replies)
Discussion started by: KingVikram
2 Replies

9. Shell Programming and Scripting

How to replace variable inside the variable

hi sir, i need your help for this script inside /rnmucdr/ednms05/ken/xMNBDF045_Script.sql content variable like this select * from invoice where bill_date=$BILLDATE and startNum=$STARTPARTNNUM and total_partn=$TOTALPARTN if i just paste this replace with the $SCRIPT it works great,if... (31 Replies)
Discussion started by: mani_um
31 Replies

10. Shell Programming and Scripting

ksh: A part of variable A's name is inside of variable B, how to update A?

This is what I tried: vara=${varb}_count (( vara += 1 )) Thanks for help (4 Replies)
Discussion started by: pa3be
4 Replies
Login or Register to Ask a Question