Possible to use /usr/bin/watch to call a function?


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# 1  
Possible to use /usr/bin/watch to call a function?

I want to have a script both define functions and have the ability to run an external program calling one of them. This is the simplified construct:

Code:
#!/bin/bash
foo() {
  echo "this is foo"
}

bar() {
  echo "this is bar"
}

case "$1" in
  one)
    foo
    ;;
  two)
    export bar
    /usr/bin/watch bar
    ;;
  *)
    echo $0 "{one|two}"
    exit 0
    ;;
esac

So if I invoke /path/to/script one the foo function runs and it exits as expected. I want to ability to run the bar function as if it were a stand-alone program via `/usr/bin/watch bar` but this doesn't work as expected.

Code:
$ /path/to/script two
Every 2.0s: bar                                                                         Mon Jul 30 02:16:25 2012

sh: bar: command not found

How can I accomplish it?

---------- Post updated at 03:18 AM ---------- Previous update was at 02:16 AM ----------

Solved...
Code:
export -f bar

# 2  
Quote:
Originally Posted by graysky
Solved...
Code:
export -f bar

Of course, but it shouldn't be enough (it isn't enough here, at least).

Code:
two)
    export -f bar
    /usr/bin/watch "bash -c bar"
    ;;

--
Bye
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