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awk syntax error

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# 1  
Old 06-17-2005
awk syntax error
Code:
mVar=0

count=`awk -F, '( ( $2 ~ /^GIVEUP$/ && $3 ~ /^NEW$/ ) || ( $2 ~ /^SPLIT$/ && $3 ~ /^NEW$/ ) || ( $2 ~ /^OPTION$/ && $3 ~ /^NEW$/ ) || ( $2 ~ /^OPTIONSPLIT$/ && $3 ~ /^NEW$/ ) ) { count++ } END { print count }' myCSV.csv
    myVar=`expr $myVar + $count`

Can I do this? I get a syntax error.
It works if I remove the 2nd two pairs of "or" operators.
# 2  
Old 06-17-2005
I didn't find the patience to count all the different types of brackets (I presume a miscount of them is causing the error), but even if the statement would work it would be pretty bad style (read: nearly unreadable for anybody else) so take the malfunction as a stroke of luck.

It is far easier to read to do something (only the skeleton) like:

Code:
BEGIN {
    count=0;
}

{
if( $2 ~ /^GIVEUP$/ && $3 ~ /^NEW$/ )
     count ++;

if( $2 ~ /^SPLIT$/ && $3 ~ /^NEW$/ )
     count ++;

if( ....

}
END {
     print count;
}

This would make clear at first glance what you are doing. The times of "if it was hard to write it should be hard to read (and even harder to understand)" are over by now.

bakunin
# 3  
Old 06-18-2005
The OP's obfuscated code works fine for me (GNU awk).... my hunch is the omission of the closing backtick.....

Cheers
ZB
# 4  
Old 06-20-2005
Code can be simplified...
Code:
count=$(awk -F, '$2 ~ /^(GIVEUP|SPLIT|OPTION|OPTIONSPLIT)$/ && $3 == "NEW" { count++ } 
                 END { print count }' myCSV.csv)

# 5  
Old 06-20-2005
very appreciative
ah, thanks guys.
i'm always interested in writing better, easier to understand code, and this post definitely helped out in that department
Last edited by yongho; 06-20-2005 at 11:19 AM..
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