[^]]* that means all characters but "]" zero or more times. \[[^]]*\] on "[brackettext1] some other text [brackettext2] some different text"
will find "[brackettext1]"
but \[.*\]
will find "[brackettext1] some other text [brackettext2]"
And to keep the bracket text:
Code:
echo 'hgfd[xtd] 123' | sed -E 's/\[([^]]*)\]/\1/'
I know that [ expression ] in regexp means that: match the expression .
And the ^ in expression means "not include".
My question is:
1. If Metacharacter appears within [ expression ] , which means the character itself, for example, in \[[^]]*\], why does it not neccessary need to be escaped? Is it a common rule?
2. echo 'hgfd[xtd] 123' | sed -E 's/\[([^]]*)\]/\1/', what does -E means?
3. If I want to delete all the "[" and "]" like this: just match "[" or "]" and replace it with "", the code like sed s; [ [ ] ] ;; . It doesn't work. how to modify?
To put it simple.
Source string: abc[[4545[]]]adfd[[[[asfdsfsf[][[[][][asdf. I want to delete all the "[" and "]"
4. vgersh99's code.echo 'hgfd[xtd] 123' | sed 's/\[[^]]*\]//1', what does the last number: 1 means?
Thanks a lot.
I know that [ expression ] in regexp means that: match the expression .
And the ^ in expression means "not include".
My question is:
1. If Metacharacter appears within [ expression ] , which means the character itself, for example, in \[[^]]*\], why does it not neccessary need to be escaped? Is it a common rule?
because sed knows how to deal with 'nested' '[]'.
Quote:
Originally Posted by painless
2. echo 'hgfd[xtd] 123' | sed -E 's/\[([^]]*)\]/\1/', what does -E means?
'-E' - is for Extended Regex (in some sed implementations.
Quote:
Originally Posted by painless
3. If I want to delete all the "[" and "]" like this: just match "[" or "]" and replace it with "", the code like sed s; [ [ ] ] ;; . It doesn't work. how to modify?
To put it simple.
Source string: abc[[4545[]]]adfd[[[[asfdsfsf[][[[][][asdf. I want to delete all the "[" and "]"
echo ' abc[[4545[]]]adfd[[[[asfdsfsf[][[[][][asdf' | sed 's/[][]//g'
Quote:
Originally Posted by painless
4. vgersh99's code.echo 'hgfd[xtd] 123' | sed 's/\[[^]]*\]//1', what does the last number: 1 means?
Hello,
I could not remove brackets with text contents
myfile:
Please remove the bracket with text
I wish to remove:
I tried:
sed 's/\//' myfile
It gives:
Please remove the bracket with text A1
I expect:
Please remove the bracket with text
Many thanks
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