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Wildcard in ls

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# 1  
Old 07-22-2012
Wildcard in ls
Hi Experts,

I want to use ls in the below form:

Code:
ls -l *.{txt,TXT} (working fine)

but when i am declaring a variable,

Code:
VAR="*.{txt,TXT}"

ls -l $VAR is not working. Please help.

Thanks.
Last edited by Scott; 07-22-2012 at 02:02 PM.. Reason: Code tags
# 2  
Old 07-22-2012
Code:
eval ls -l "$VAR"

# 3  
Old 07-22-2012
That's odd that the {} wouldn't be evaluated when used that way, since * definitely is, but it does look like you need eval.
# 4  
Old 07-22-2012
Thanks all for your help.

Even this is working fine eval ls -l $VAR.. without quotes.
# 5  
Old 07-22-2012
Quote:
Originally Posted by Corona688
That's odd that the {} wouldn't be evaluated when used that way, since * definitely is, but it does look like you need eval.
bash performs brace expansion before parameter expansion, so the braces in $VAR aren't special.

However, this would work in ksh, since it performs brace expansion after paremter expansion (just before pathname expansion).

Regards,
Alister
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