help to get the biggest partition with awk


 
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Top Forums Shell Programming and Scripting help to get the biggest partition with awk
# 8  
Old 07-20-2012
Quote:
Originally Posted by yanglei_fage
can you point me where is wrong for mine
You use the "fi" token which is a shell script thing and doesn't exist in awk.
Quote:
I want to out put /dev/sda3. which is the max partition
Code:
awk '/^\// {if($3-$2>m){m=$3-$2;p=$1}} END {print p}'

# 9  
Old 07-20-2012
Quote:
Originally Posted by yanglei_fage
can you point me where is wrong for mine
Code:
awk '/^\// {if ($3-$2>max) max=$3-$2 fi} END {print max}'

fi is not an awk keyword. In your code it is an uninitialized variable. Subtraction has higher precedence than string concatenation. The result of the subtraction is converted to a string when it is concatenated with the empty string in fi. max is now a string value. The next time it is compared using >, the comparison is done lexicographically, not numerically.

Regards,
Alister
# 10  
Old 07-20-2012
To output the /dev/sda3 and not the maximum size, on all the solutions when you change the value of max just add something like dv=$1. Then at the END print dv.
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