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need to pass value while running the script

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Top Forums Shell Programming and Scripting need to pass value while running the script
# 1  
Old 07-19-2012
need to pass value while running the script
hi
i am trying to write a script in which i want to pass a value and that value should be
compare with a value which was already define in a script .
if the value is correct the sj=how access esle show access denied.

below is my script: this is not working.
Code:
#!/bin/ksh
  echo "The value of the first argument to the script :" $1
  p=$1
  passwod="asr"
  read p
  if  “$p" == "$password" ]; then
          echo "You have access!"
  else
          echo "ACCESS DENIED!"
  fi

i also make few changes that also not help me.
below is the changes i made .
Code:
#!/bin/ksh
  read $1
  echo "The value of the first argument to the script :" $1
  passwod="asr"
  #read $1 
  if  [`$1` == "$password" ]; then
          echo "You have access!"
  else
          echo "ACCESS DENIED!"
  fi

but getting below o/p
Code:
$ e3 asr

The value of the first argument to the script : asr
                                   -> "at this blank space cursor blink then ii again enter the asr"
e3[8]: asr:  not found.
e3[8]: test: 0403-004 Specify a parameter with this command.
ACCESS DENIED!
$

please suggest
# 2  
Old 07-19-2012
Code:
#!/bin/ksh

echo "The value of the first argument to the script: $1"
password="asr"

if  [ $1 == "$password" ]
then
    echo "You have access!"
else
    echo "ACCESS DENIED!"
fi

Quote:
Originally Posted by scriptor
"at this blank space cursor blink then ii again enter the asr"
read is used to take input from user. That's why you saw what you quoted.
# 3  
Old 07-19-2012
Java
this mean that "read" will not read the parameter which i pass initially.
and i have to enter value for "read" again?
# 4  
Old 07-19-2012
passwod="asr" and if has password
Look at you script you have defined the variable passwod and you are testing the condition with $password
# 5  
Old 07-19-2012
Java
thx for pointing out. but still getting err.

Code:
$ cat e3
#!/bin/ksh
read $1
echo "The value of the first argument to the script :" $1

password="asr"

if  [$1 == "$password" ]; then
        echo "You have access!"
else
        echo "ACCESS DENIED!"
fi

below is the o/p
Code:
$ e3 asr
asd
The value of the first argument to the script : asr
e3[8]: [asr:  not found.
ACCESS DENIED!
$

in this script i want to pass $1 value to password but this is not happening
# 6  
Old 07-19-2012
@scriptor: Please read post #2 above.
# 7  
Old 07-19-2012
i am not getting my answer

this mean that "read" will not read the parameter which i pass initially.
and i have to enter value for "read" again?

in this script i want to pass $1 value to password but this is not happening


correction already made.which was pointed out by maverick_here
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