Script to kill process


 
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# 1  
Old 06-13-2005
Error Script to kill process

Hello guys,

I have a process named monitoreo, with 'monitoreo start' my process start until i kill them, now i want to do 'monitoreo stop' to kill them.

After 'monitoreo start' i have this process running:

Code:
ps -af
     UID   PID  PPID  C    STIME TTY      TIME CMD
     ati 10958  1495  0 15:14:19 pts/2    0:00 sleep 5
     ati 10959 27456  0 15:14:21 pts/2    0:00 ps -af
     ati  1495     1  0 14:59:43 pts/2    0:01 /bin/bash ./monitoreo start

no i want to kill it with monitoreo stop, i need to save the pid of 'monitoreo start' to kill them later, how i can do it?

I try with

Code:
ps -aef | grep monitoreo | grep -v grep | cut -d" " -f8 > pid_file

then i try to kill -9 the cat of pid_file but somethimes is -f8 and sometimes is -f7 cuz there are spaces.... that have sence?
# 2  
Old 06-13-2005
Code:
#!/bin/ksh

kill $(ps -ef | nawk '/monitoreo start/ { print $2}'}

# 3  
Old 06-14-2005
Quote:
Originally Posted by Lestat
Hello guys,
Code:
ps -aef | grep monitoreo | grep -v grep | cut -d" " -f8 > pid_file

There are two problems with this line:

1. by using double quotes to surround the space in the '-d'-option of "cut" you don't guard this space from shell expansion in every case. Maybe this is not causing you problems right now, but better to use single quotes: ... | cut -d' ' ...

2. you use a single space as a field delimiter. By looking at the output of 'ps' you will notice that it is in tabbed format, that is: with more than one blank separating the fields. Either use 'cut' with the '-c' (column) option (not recommendable) or change the occurrance of one or more spaces to one space before:

... | sed 's/<space><space>*/<space>/g' | cut -d' ' ...

replace the <space> to real space characters above.

Hope this helps

bakunin
# 4  
Old 06-14-2005
Try this,

kill -9 `ps -aef | grep monitoreo | grep -v grep | awk '{print $2}'`

This will avoid problems of spaces and delimiters as awk itself takes care.

Check it out.
Smilie
# 5  
Old 06-15-2005
Quote:
Originally Posted by amit_sapre
... as awk itself takes care.
true - you forgot to mention, though, that it uses up lots of system resources in doing so.

What one thinks about wasting resources is left to everybodies judgement.

bakunin
# 6  
Old 06-15-2005
Amit, your post help me, I just have to add some characters and at the end the solution was:
Code:
kill -9 `ps -aef | grep 'monitoreo start' | grep -v grep | awk '{print $2}'`

Thanx
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